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just olya [345]
4 years ago
5

What is the difference between a solute and a solvent?

Chemistry
1 answer:
Nataly_w [17]4 years ago
5 0
A solute is the substance to be dissolved for example sugar

The solvent is the one doing the dissolving for example water
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THIS IS SCIENCE
lana [24]
I'm guessing D or C, remember that the noble gases cannot combine
5 0
3 years ago
The energy absorbed or released when a neutral atom gains one electron
jenyasd209 [6]
It’s one... electron affinity
7 0
3 years ago
Read 2 more answers
What is the temperature of 1.2 moles of helium gas at 2.57 ATM if it occupies 15.5L of volume
agasfer [191]
We will assume helium to behave as an ideal gas and apply the ideal gas law:
PV = nRT
For pressure measured in atmospheres and volume measured in liters, the value of the molar gas constant is 0.082. Therefore:
T = PV / nR
T = (2.57 x 15.5) / (1.2 x 0.082)
T = 404.8 Kelvin
8 0
3 years ago
Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of ammonium phosphate and nickel(
densk [106]

Answer:

2PO_4^{3-}(aq)+3Ni^{2+}(aq)\rightarrow Ni_3(PO_4)_2(s)

Explanation:

Hello,

In this case, the molecular chemical reaction is:

(NH_4)_3PO_4(aq)+NiBr_2(aq)\rightarrow NH_4Br(aq)+Ni_3(PO_4)_2(s)

Thus, by considering the ionic species we have:

NH_4^+(aq)+2PO_4^{3-}(aq)+3Ni^{2+}(aq)+Br^-(aq)\rightarrow NH_4^+(aq)+Br^-(aq)+Ni_3(PO_4)_2(s)

Wherein the ammonium and bromide ions are spectator ions since nickel (II) phosphate is largely insoluble in water, therefore, the net ionic equation is:

2PO_4^{3-}(aq)+3Ni^{2+}(aq)\rightarrow Ni_3(PO_4)_2(s)

Best regards.

7 0
3 years ago
Uranium–232 has a half–life of 68. 9 years. A sample from 206. 7 years ago contains 1. 40 g of uranium–232. How much uranium was
ioda

Half-life can be given as the time required by the substance to reduce to half of its original concentration. The original mass of Uranium was 11.2 grams.

<h3>What is the expression of half-life?</h3>

The half-life for the reaction can be expressed as;

A_t=A_0(\dfrac{1}{2})^\dfrac{t}{t1/2}

Where the final mass of the product is, A_t=1.40\;\rm g

The time for the reduction is given as, t=206.7\;\rm years

The half-life of the compound is given as, t1/2=68.9\;\rm years

The original concentration (A_0) of the Uranium is given as,

\rm 1.40\;g=\textit A_0(\dfrac{1}{2} )^{\dfrac{206.7}{68.9}}\\\\1.40\;g= \textit A_0(\dfrac{1}{2} )^3\\\\\textit A_0=11.2\;\rm grams

The original mass of uranium-232 has been 11.2 grams.

Learn more about half-life, here:
brainly.com/question/24710827

8 0
2 years ago
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