Answer:
A. 4 CPUs and 6 megabyte cache memory
B. 1.3157 x10^-9 nanoseconds
Explanation:
The Intel core i5 7500 is a seventh generation central processing unit with a 4 CPU core and a 6 megabyte cache memory. It executes task at a clock cycle of 5 clock cycle at a speed of 3.8 GHz.
The relationship between frequency and clock cycle is,
Clock cycle = 1 / ( frequent).
So, One clock cycle = 1 / 3.8 GHz
= 0.3 x10^-9
For five clock cycles = 5 x 0.3 x10^-9
= 1.3157 x10^-9 nanoseconds.
Answer:
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
Explanation:
The Worst case will happen when f(a) > 2*f(b) ; f(b) > 2*f(c) ; f(c) > 2*f(d) ; f(d) > 2*f(e) and f(e) > 2*f(f).
Where f(x) is frequency of character x.
Lets consider the scenario when
f(a) = 0.555, f(b) = 0.25, f(c) = 0.12, f(d) = 0.05, f(e) = 0.02 and f(f) = 0.005
Please see attachment for image showing the steps of construction of Huffman tree:- see attachment
From the Huffman tree created, we can see that endcoding e() of each character are as follows:-
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
e(e) = 11110
e(f) = 11111
So we can see that maximum length of encoding is 5 in this case.
Answer:
First you read the question and numbers, then you use the numbers in the correct way and you try reallllyyy hard, you will find your answer! Hope this helps! :D
Answer: All of the above
Explanation:
All the above listed point serves as security measures to safeguard our computing devices and systems.