a formula for the general term a n of the sequence assuming the pattern of the first few terms continues. { − 13/3 , 16/9 , − 19/27 , 22/81 , − 25/243 , ... } is 
.
<u>Step-by-step explanation:</u>
Here we have , the pattern of the first few terms continues. { − 13/3 , 16/9 , − 19/27 , 22/81 , − 25/243 , ... } . We need to find a formula for the general term a n of the sequence . Let's find out:
In this question there is no such technique , instead we have to use our brain to manipulate the pattern as :
1st term = − 13/3 = 
2nd term = 16/9 = 
3rd term = − 19/27 = 
4th term = 22/81 = 
5th term = − 25/243 = 
nth term =
Therefore, a formula for the general term a n of the sequence assuming the pattern of the first few terms continues. { − 13/3 , 16/9 , − 19/27 , 22/81 , − 25/243 , ... } is .
Length of prism = 1/3 x 6 = 2 inches
Width of prism = 1/3 x 4 = 4/3 inches
Height of prism = 1/3 x 8 = 8/3 inches
Volume of prism = 2 x 4/3 x 8/3 = 7 1/9 cubic inches
Answer:
30 , 45 , 51 , 39
Step-by-step explanation:
You just add up the numbers until you get 165
Answer:
A. x=0 and x=4
Step-by-step explanation:
The roots of a quadratic function are the x intercepts of the parabola. In this case, the roots are 0 and 4 because the parabola intercepts the x axis twice in these points.
Your answer is A. x=0 and x=4
Hope I helped!
Let the sides of the polygon (which is a triangle, by the way) be x, y and z. The sum of x, y and z is the perimeter of the original poly, and this equals 18 cm.
Letting f be the scale factor, f(18 cm) = 12 cm. Then f=2/3.
The dilation reduces the size of the polygon by a factor of 1/3, producing a similar polygon which is 2/3 the size of the original one.
In each case we have 3 side lengths but no angles. We can use Heron's formula to obtain the area in each case. Look up Heron's formula. In one version of this formula, p is half the actual perimeter, meaning that p is 18 cm / 2 for the first triangle and 12 cm / 2 for the second.
The area of the first triangle would be
A18 = sqrt( 9(9-x)(9-y)(9-z) )
whereas
A12 = sqrt( 6(6-x*a)(6-y*a)(6-z*a) ), where a represents the dilation factor 2/3.
Then the ratio of the areas of the 2 triangles is
sqrt( 6(6-x*a)(6-y*a)(6-z*a) )
---------------------------------------
sqrt( 9(9-x)(9-y)(9-z) )
