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Masja [62]
3 years ago
11

A circle has a diameter of 9cm

Mathematics
1 answer:
Katen [24]3 years ago
8 0

For the square to fit inside the circle without touching it, the diagonal of the square needs to be less than the diameter of the circle.

Using the Pythagorean theorem we can calculate the diagonal of the square:

X = SQRT(5^2 + 5^2)

X = SQRT(25 + 25)

X = SQRT(50)

X = 7.07

The diagonal of the square is 7.07 cm, which is less than the diameter of the circle, 9cm, so it will fit .

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first, consider that 25 = 5^2, and -25 = -1*25 = -1*5^2.

Then, you can write:

\sqrt[]{-25}=\sqrt[]{(-1)(25)}=\sqrt[]{(-1)(5^2)}=5\sqrt[]{-1}=5i

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3 years ago
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Answer:

X = -12.54 (I am a Math Class Topper in both 6th Grade an 7th Grade)

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5 x .27 = 1.35

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----------------------------------

1.35 + X - .81 = -12

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X = -12.54

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Answer:

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