Let
A(4,0)
B(12,5)
C(20,10)
we know that
The x-intercept of the line is the value of x when the value of y is equal to zero
The y-intercept of the line is the value of y when the value of x is equal to zero
The point A(4,0) is the x-intercept of the line
<u>Find the slope AB</u>
m=(y2-y1)/(x2-x1)
mAB=(5-0)/(12-4)--------> mAB=5/8
<u>with the slope m and the point A(4,0) find the equation of the line</u>
y-y1=m*(x-x1)----------> y-0=(5/8)*(x-4)-------> y=(5/8)x-2.5-----> y=0.625x-2.5
<u>Find the y-intercept</u>
For x=0
y=0.625*0-2.5---------> y=-2.5
the y-intercept is the point (0,-2.5)
therefore
<u>the answer is</u>
the x-intercept is the point (4,0)
the y-intercept is the point (0,-2.5)
see the attached figure to better understand the problem
