Answer:
![The\ weight\ of\ the\ 50\ erasers\ be\ \frac{4000}{n}\ grams.](https://tex.z-dn.net/?f=The%5C%20weight%5C%20of%5C%20the%5C%2050%5C%20erasers%5C%20be%5C%20%5Cfrac%7B4000%7D%7Bn%7D%5C%20grams.)
Step-by-step explanation:
As given
if n erasers have a weight of 80 grams .
I.e
n erasera = 80 grams.
1 erasers weight .
![1\ erasers\ weight = \frac{80}{n}](https://tex.z-dn.net/?f=1%5C%20erasers%5C%20weight%20%3D%20%5Cfrac%7B80%7D%7Bn%7D)
Now find out the weight of the 50 erasers.
![Weight\ of\ 50\ erasers = \frac{50\times 80}{n}\ grams](https://tex.z-dn.net/?f=Weight%5C%20of%5C%2050%5C%20erasers%20%3D%20%5Cfrac%7B50%5Ctimes%2080%7D%7Bn%7D%5C%20grams)
Simplify the above
![Weight\ of\ 50\ erasers = \frac{4000}{n}\ grams](https://tex.z-dn.net/?f=Weight%5C%20of%5C%2050%5C%20erasers%20%3D%20%5Cfrac%7B4000%7D%7Bn%7D%5C%20grams)
![Therefore\ the\ weight\ of\ the\ 50\ erasers\ be\ \frac{4000}{n}\ grams.](https://tex.z-dn.net/?f=Therefore%5C%20the%5C%20weight%5C%20of%5C%20the%5C%2050%5C%20erasers%5C%20be%5C%20%5Cfrac%7B4000%7D%7Bn%7D%5C%20grams.)
Answer:
V= 105cm^3
Step-by-step explanation:
V=volume
(1/3)V+40=(5/7)V
(5/7)V-(1/3)V=40
(15/21)V-(7/21)V=40
(8/21)V=40
(21/8)(8/21)V=(21/8)(40
V=21*5
V=105 cm3
(1/3)(105)=35, 35+40=75, 75/105=15/21=5/7
Answer:
31 degrees
Step-by-step explanation:
Not sure where angle B is, but
90-59= 31
Combine like terms
2m and -4m are like terms while 3m^2 isnt. So, leave 3m^2 as it is and combine the other set. 2m-4m = (-2m). Therefore, your answer should be 3m^2 - 2m
Answer:
1
Step-by-step explanation:
First find f(0) and g(0). These are the values where x=0 in each function.
f(0) = 1+0 = 1
g(0) = 1^2 - 1 = 1-1 = 0
So f(0) = 1 and g(0) = 0.
Now substitute f(0) = 1 into g(t).
g(1) = 1^2 -1 = 1-1 = 0.
So g(f(0)) = 0.
Now substitute g(0) = 0 into f(t).
f(0) = 1 + 0 = 1.
So f(g(0)) = 1.
Add the values 0 and 1 to get 0+1 = 1.