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faltersainse [42]
3 years ago
8

Select the correct answer. Consider these equations: f(x)=

"x^{3}" alt="x^{3}" align="absmiddle" class="latex-formula">+3 g(x)=x^{2}+2 Approximate the solution to the equation f(x) = g(x) using three iterations of successive approximation. Use this graph as a starting point.

Mathematics
2 answers:
ra1l [238]3 years ago
7 0

Answer:

A

Step-by-step explanation:

The solution to these two graphs will be when they are equal. Therefore:

x^3+3=x^2+2 \\\\x^3-x^2+1=0 \\\\x\approx -0.755\approx -\dfrac{13}{16}

Hope this helps!

marissa [1.9K]3 years ago
3 0

Answer:

-13/16

Step-by-step explanation:

f(x)=x^3+3

g(x)=x^2+2

We know the solution is around -1

x^3+3 = x^2 +2

Subtract x^2+2 from each side

x^3 -x^2 -1 = f(x)

We need to find the derivative

3x^2 -2x = f'(x)

Newtons method of successive approximation states

xn+1 = xn -f(xn) / f'(xn)

Function

x3−x2+1

Derivative

x⋅(3⋅x−2)

x

-0.75488

Iterations

Step x F(x) |x(i) - x(i-1)|

x1 -0.8      -0.152000 0.152000

x2 -0.75682 -0.006259 0.006259

x3 -0.75488 -0.000012 0.000012

The approximate answer is -0.75488

The closest answer given is -13/16

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Ethan went bowling on Saturday night. His scores were 128, 97, 123, and 108. What was his average score for the night?
telo118 [61]

Answer:

114

Step-by-step explanation:

97+108+123+128=456

\frac{456}{4} = 114

3 0
2 years ago
can someone pls help me? i have no idea what to do. pls show the work steps for the questions. i will mark u as
tiny-mole [99]

Ok, so the question is based on geometric progression. Remember, the formula for calculating the nth-term of a geometric progression is: a*r^{n-1}. The a in the expression stands for the 1st term of the sequence, and r is the common ratio of the elements of the sequence. Now let's take a look at the problem.

"A ping pong ball has a 75% rebound ration". We can infer that our common ratio, r, is 75% which is 0.75.

"When you drop it from a height of k feet...", this means the first height you drop it from, a.k.a, the first term.

Now going back to the expression, the nth-term = a*r^{n-1}, we can substitute our common ration, 0.75 with r, and our 1st term, k, with a. This becomes: k * 0.75^{n-1}. This becomes our expression.

a. The highest height achieved by the ball after six bounces. Our nth-term here is 6, so let's use our expression to find the 6th term. n_{6} = 235 * 0.75^{6-1} = 235*0.75^{5} = 235*0.2373 = 55.7655ft

b. The total distance travelled by the ball when it strikes the ground for the 12th time. This involves the use of the sum of elements in the geometric progression. The formula for that is \frac{a(1 - r^{n})}{1-r}, provided that r is less than 1, which it is in this case, since 0.75 is less than one. Our nth-term here is 12, so we substitute.

\frac{235(1-0.75^{12})}{(1-0.75)} = 910.2242ft

6 0
3 years ago
Just do these two problems for me and I’ll be so happy
sveticcg [70]
5. y = x + 7
6. y = -x + 1
4 0
2 years ago
Reflect the figure over the line <br> x<br> =<br> 2<br> x=2.
inessss [21]

2 = 2????

Thats what Im getting it from.

Since x is 2 then it would still be 2=2 in simple term.

7 0
3 years ago
Please help ASAP!!!!!!!!!
algol [13]

Answer:

A = 23.6 units^2

Step-by-step explanation:

Let the base be 8 (as shown).

Find the height of the triangle:   Find the supplement of the 100 degree angle; it is (180 - 100), or 80 degrees.  The side "opposite" this 80-degree angle is the height of the triangle:

   

                               height      

sin 80 degrees = ---------------

                                    6

and so the height of the triangle is h = 6 sin 80 degrees, or 5.91 units.

The area of the triangle is found using A = (1/2)(base)(height), which here amounts to:

A = (1/2)(8 units)(5.91 units), or

                                                       A = 23.64 units^2, or A = 23.6 units^2

3 0
3 years ago
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