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3 years ago

A cruise ship is traveling at a speed of

Mathematics

1 answer:

Art [367]3 years ago

6 0

Answer:

1 mile = 1760 yards

20 * 1.151 = 23.02

23.02 * 1760 = 40,515.2

40,515.2 / 60 = 675.243~

675.243~ / 60 = 11.2542~

They are traveling 11.25 yards per second

I took the number of knots multiplied by the approximate miles per hour. Then multiplied that by the number of yards in a mile, and then divided that by the number of minutes in an hour, and divided that by the number of seconds in a minute. That is how I got the answer!

when rounded to tens, the answer is 11

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A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and

pav-90 [236]

Answer:

ans=13.59%

Step-by-step explanation:

The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean $\mu$ and standard deviation $\sigma$ , we have these following probabilities

$Pr(\mu - \sigma \leq X \leq \mu + \sigma) = 0.6827$

$Pr(\mu - 2\sigma \leq X \leq \mu + 2\sigma) = 0.9545$

$Pr(\mu - 3\sigma \leq X \leq \mu + 3\sigma) = 0.9973$

In our problem, we have that:

The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months

So $\mu = 53, \sigma = 11$

So:

$Pr(53-11 \leq X \leq 53+11) = 0.6827$

$Pr(53 - 22 \leq X \leq 53 + 22) = 0.9545$

$Pr(53 - 33 \leq X \leq 53 + 33) = 0.9973$

-----------

$Pr(42 \leq X \leq 64) = 0.6827$

$Pr(31 \leq X \leq 75) = 0.9545$

$Pr(20 \leq X \leq 86) = 0.9973$

-----

What is the approximate percentage of cars that remain in service between 64 and 75 months?

Between 64 and 75 minutes is between one and two standard deviations above the mean.

We have $Pr(31 \leq X \leq 75) = 0.9545 = 0.9545$ subtracted by $Pr(42 \leq X \leq 64) = 0.6827$ is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.

To find just the percentage above the mean, we divide this value by 2

So:

$P = {0.9545 - 0.6827}{2} = 0.1359$

The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.

4 0

3 years ago

WILL GIVE MEDAL!! A flight of stairs is supported by two columns as shown. What is the distance from the base of the stairs to t

scoray [572]

There are two triangles: a small one to the left and a big one, which includes the small one. They both have a common angle (the leftmost angle) and since (we can assume) the two columns meet the floor at right angles, they both have two equal angles. This means they are similar (AAA).

Let the distance of the base of the stairs to the tallest column be d.

Because matching sides of similar triangles are in the same ratio,
4 / 6 = d / (6 + 12)
4 / 6 = d / 18
(4 * 18) / 6 = d
d = 12

The answer is C

6 0

3 years ago

Read 2 more answers

A movie theater sold a total of 205 tickets to a movie, for a total of $1621. Adult tickets were $9 and student tickets were $5.

77julia77 [94]

Let x represent the number of adult tickets sold.

Let y represent the number of student tickets sold.

We were told that the movie theater sold a total of 205 tickets to a movie. This means that

x + y = 205

Adult tickets were $9 and student tickets were $5. This means that the cost of x adult tickets and y student tickets is 9x + 5y. If the total cost of the tickets was $1621, it means that

9x + 5y = 1621

From the first equation, x = 205 - y

We would substitute x = 205 - y into 9x + 5y = 1621. Thus, we have

9(205 - y) + 5y = 1621

1845 - 9y + 5y = 1621

- 9y + 5y = 1621 - 1845

- 4y = - 224

y = - 224/- 4

y = 56

x = 205 - y = 205 - 56

x = 149

Thus, 56 student tickets were sold

3 0

1 year ago

How many inches smaller is a 6.17 inch worm than a 10.63 inch worm?

mario62 [17]

The worm is approximately 4.46 inches smaller than the other one.

8 0

2 years ago

after a 20% reduction, you purchase a television for $336. What was the television's price before the reduction?

Naily [24]

The price would be $403.20 before reduction and you multiple $336 by 1.2 to figure this out

7 0

3 years ago