Answer:
Step-by-step explanation:
<h3>Part B</h3>
Assumed the dimensions of the top and bottom parts are identical.
Since the cylindrical part has total height of 1.8 cm and the hemisphere volume is transferred to bottom part and the cone part is still full, the value of h is the difference of the total height of cylinder and full part of the top section of cylinder:
- h = 1.8 cm - 0.3 cm = 1.5 cm
<h3>Part C</h3>
Find the volume of sand in the bottom part. It consists of a hemisphere and a cylinder of 1.5 cm height.
- V(cylinder) = πr²h = 3.14*(2.6/2)²*1.5 ≈ 7.96 cm³
- V(hemisphere) = 2/3πr³ = 2/3*3.14*(2.6/2)³ ≈ 4.6 cm³
<u>Total sand in the bottom part:</u>
<u>Time taken:</u>
- 12.56 / 0.05 = 251.2 seconds = 4 min 11.2 seconds
Answer to this math equation: 46744733
154
Subtract $1060 from $5680 to get $4620 > divide $4620 by $30 to get 154 > 154 students can attend
<h3>
Answers:</h3>
- ST = 23
- RU = 8
- SV = 5
- SU = 10
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Explanation:
Focus on triangles SVT and UVT.
They are congruent triangles due to the fact that SV = VU and VT = VT. From there we can use the LL (leg leg) theorem for right triangles to prove them congruent.
Since the triangles are the same, just mirrored, this means ST = UT = 23.
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Following similar reasoning as the previous section, we can prove triangle RVU = triangle RVS.
Therefore, RS = RU = 8
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SV = VU = 5 because RT bisects SU.
Bisect means to cut in half. The two smaller pieces are equal.
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SU = SV + VU = 5+5 = 10
Refer to the segment addition postulate.
