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3 years ago

8x-3y=3 2x+y=-15 solve by eliminaion.

Mathematics

2 answers:

Andrei [34K]3 years ago

6 0

8x - 3y = 3 -> y = 8/3x - 1
2x + y = -15 -> y = 2x - 15

Darina [25.2K]3 years ago

5 0

Answer:

8x - 3y = 3 -> y = 8/3x - 1

2x + y = -15 -> y = -2x - 15

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Solve system using eliminations 2x+4y=22 2x-2y=-8

KATRIN_1 [288]

$2x+4y=22 \\
2x-2y=-8 \ \ \ |\times (-1) \\ \\
2x+4y=22 \\
\underline{-2x+2y=8} \\
2x-2x+4y+2y=22+8 \\
6y=30 \ \ \ |\div 6 \\
y=5 \\ \\
2x-2y=-8 \\
2x-2 \times 5=-8 \\
2x-10=-8 \ \ \ |+10 \\
2x=2 \ \ \ |\div 2 \\
x=1 \\ \\
\boxed{(x,y)=(1,5)}$

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3 years ago

Could someone Help me please!

Aliun [14]

C = 2 pi r
C = 2 x 3.14 x 5
C = 31.4 yd

A = pi r^2
A = 3.14 x 5^2
A = 3.14 x 25
A = 78.5 yd^2

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3 years ago

If Brian biked at an average speed of 12.2 miles per hour for 1.45 hours, you can find the total distance by multiplying Explain

Alenkinab [10]

Answer:

The distance he traveled is 17.69.

Step-by-step explanation:

Simple you'll need to multiply 12.2 times 1.45. Which should equal a total distance of 17.69

6 0

3 years ago

Read 2 more answers

In AIJK, j = 800 cm, k = 240 cm and

abruzzese [7]

answers 800 cm k=240 ZI=173°

8 0

3 years ago

find the standard form of equation of a line perpendicular to 4X plus 5Y equals 40 that includes the point -10, -3

snow_tiger [21]

The equation of line in standard form is 5x - 4y = -38

Solution:

Given that we have to find the equation of line perpendicular to 4x + 5y = 40 that includes the point (-10, -3)

The equation of line in slope intercept form is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given equation of line is:

4x + 5y = 40

Rearranging to slope intercept form, we get

5y = -4x + 40

$y = \frac{-4}{5}x + \frac{40}{5}\\\\y = \frac{-4}{5}x + 8$

On comparing the above equation with eqn 1,

$m = \frac{-4}{5}$

We know that product of slope of line and slope of line perpendicular to given line is equal to -1

Therefore,

$\frac{-4}{5} \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{5}{4}$

Now find the equation of line with slope 5/4 and passing through (-10, -3)

Substitute $m = \frac{5}{4}$ and (x, y) = (-10, -3) in eqn 1

$-3 = \frac{5}{4}(-10) + c\\\\-3 = \frac{-25}{2} + c\\\\c = -3 + \frac{25}{2}\\\\c = \frac{-6 + 25}{2}\\\\c = \frac{19}{2}$

Substitute $c = \frac{19}{2}$ and $m = \frac{5}{4}$ in eqn 1

$y = \frac{5}{4}x + \frac{19}{2}$

The standard form of an equation is Ax + By = C

Therefore,

$\frac{5}{4}x - y = -\frac{19}{2}\\\\\frac{5x - 4y}{4} = \frac{-19}{2}\\\\5x - 4y = -38$

Thus the equation of line in standard form is found

4 0

3 years ago