Answer:
60:70
Step-by-step explanation:
Answer:
Danny will watch all of them on the same day again on August 31
Step-by-step explanation:
Here, we have a word problem.
The shows and frequency of watching are;
Show A Every 2 days
Show B Every 3rd day
Show C Every 5th day
Show D Every 10th day
Danny watched all four shows on August 1, therefore, the day he will watch all four shows can be found by finding the Lowest Common Multiple, LCM of the frequency of his watching each of the shows. That is, the LCM of 2, 3, 5 and 10
Therefore we have, since 10 is the highest frequency and 3 is not a factor of 10, then the LCM that applies to 3 and 10 is 3×10 = 30.
Since the other frequencies are also a factor of 30, then the LCM of 2, 3, 5, and 10 is 30
Therefore, Danny will watch all four shows again on the same day again in 30 days after August 1. That is August (1 + 30) = August 31.
$100 - $49.95 = $50.05
You have $100, and just renting costs $49.95, leaving $50.05 left.
$50.05 / $0.39 = 128.3
Out of your money left ($50.05) you divide my how much it costs in a day, to get how many miles you can go.
The answer is 128.3, but if you were going a round trip (there and back) you would do 128.3 / 2 = 64.16, meaning you can go 64 miles and come back, all for a hundred dollars (still 128 miles in total though)
Answer:
Step-by-step explanation:
2 1/8-3/4
17/8-3/4
17/8-6/8
11/8
6 3/5-3 4/5
33/5-19/5
14/5
