Answer:
1:1:1:1 walnut comb
Explanation:
If a cross is made between a female who is RRpp (rose comb) and a male who is rrPP (pea comb) then:
P: RRpp x rrPP
F1: RrPp RrPp RrPp RrPp
This means that all of the offspring in F1 generation will have heterozygous genotype (at both loci). Since it contains both dominant alleles, the phenotype is walnut comb.
Autosomal dominant condition occurs when alleles of genes present on chromosomes in the autosomes (somatic) mask the effect of the other allele.
They can produce a light brown kid and the chances of producing this is 50%.
- Light brown color is dominant to black. A light brown male is mated to a black female, producing a black kid.
- For the two to produce a black kid which is in the recessive condition, the male has to be heterozygous for the condition (Bb).
Let light brown be (BB or Bb) and black be (bb)
Parents : B b x b b
Offspring genotype: Bb bb
Ratio: 1 : 1 (50%)
Learn more about autosomal dominance: brainly.com/question/7135379
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A process that a cell does not use to maintain homeostasis would be A. Taking in waste. This is because by doing so, the organism would posses indigestible, and excess content not needed and thus may change internal conditions for vital reactions to occur.
There are different types of biomes but,here`s my example
https://www.google.com/url?sa=i&source=images&cd=&ved=2ahUKEwjBhKrevPjeAhXym-AKHZrCCFsQjRx6BAgBEAU&url=https%3A%2F%2Fkidsbiology.com%2Fbiology-basics%2Fpolar-ice-biome%2F&psig=AOvVaw0ggrhmzAXQiH3vAVGusTXb&ust=1543542147595612
