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lilavasa [31]
3 years ago
7

An architect draws a blueprint of a house. He draws the living room on the blueprint as 4.5 in. long by 6 in. wide with a scale

of 1 in. for every 4
ft. He draws a second copy of the blueprint with a scale of 1 in. for every 3 ft. How many inches long should the living room be in this second
blueprint?
Mathematics
2 answers:
s2008m [1.1K]3 years ago
8 0

Answer:

the answer is 8.5

Step-by-step explanation:

yeet

tatiyna3 years ago
6 0

Answer:

I think the closest would be 8 :3

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What percent of 50 is 15
jarptica [38.1K]

Answer:

15 of 50 can be wriiten as:

\frac{15}{50}


Multiply both numerator & denominator by 100

\frac{15}{50} × \frac{100}{100} =  \frac{30}{100} = 30%


Hope this helps! Please mark brainliest. Have a nice day!


7 0
3 years ago
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The endpoints of a side of rectangle ABCD in the coordinate plane are at A(3, 5) and B(5, 1). Find the equation of the line that
andreyandreev [35.5K]

Answer:

2x + y = 16

Step-by-step explanation:

In rectangle side AB and side CD are parallel, so the slope of both the lines will be same it means that they are parallel to each other.

slope of line AB:

\textrm{m}=\frac{\textrm{y}_{A}-\textrm{y}_{B}}{\textrm{x}_{A}-\textrm{x}_{B}}\\\textrm{m}=\frac{5-1}{3-5}=\frac{4}{-2}=-2\\\therefore \textrm{m}=-2

slope of line CD = slope of line AB = -2

∴ equation of line CD:

\textrm{y}-\textrm{y}_{C}=\textrm{m}(\textrm{x}-\textrm{x}_{C})\\ \textrm{y}-2=-2(\textrm{x}-7)\\2\textrm{x}+\textrm{y}=16

3 0
3 years ago
translate this sentence into an equation. the product of janelles saving and 3 is 54 . use the variable j to represent janelles
gladu [14]
J+3=54
Janelles savings plus 3 is 54 ?
7 0
3 years ago
It has been reported that the probability that an individual will develop schizophrenia over their lifetime is 0.004. In a rando
Alinara [238K]

Answer:

Null hypothesis:p=0.004  

Alternative hypothesis:p \neq 0.004  

z=\frac{0.00567 -0.004}{\sqrt{\frac{0.004(1-0.004)}{3000}}}=1.449  

p_v =2*P(z>1.149)=0.2506

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion if individuals that developed schizophrenia its not significantly different from 0.004.  

Step-by-step explanation:

1) Data given and notation

n=3000 represent the random sample taken

X=17 represent the individuals developed schizophrenia in the sample

\hat p=\frac{17}{3000}=0.00567 estimated proportion of individuals developed schizophrenia in the sample

p_o=0.004 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that true proportion of people who will develop schizophrenia is different from 0.004:  

Null hypothesis:p=0.004  

Alternative hypothesis:p \neq 0.004  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.00567 -0.004}{\sqrt{\frac{0.004(1-0.004)}{3000}}}=1.449  

4) P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>1.149)=0.2506

5) Decision

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion if individuals that developed schizophrenia its not significantly different from 0.004.  

4 0
3 years ago
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