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3 years ago

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Ellen is downloading a file. After 2 minutes, there are 38.4 megabytes left to download. After 8 minutes, there is only 9.6 mega

bytes left to download. What is the size, in megabytes, of the file.?

2 answers:

atroni [7]3 years ago

7 0

Find the average download rate.
(38.4 - 9.6) / (2-8) = -4.8 mb/min

that means in the first 2 min she had downloaded 2(4.8) = 9.6 mb

38.4 mb left + 9.6 mb already downloaded = 48 mb total

Oksana_A [137]3 years ago

3 0

Answer:

The size of the file is of 48 megabytes.

Step-by-step explanation:

8-2 = 6 minutes

38.4 - 9.6 = 28.8 megabytes

As we can see, 28.8 megabytes were downloaded in 6 minutes. Assuming a constanct and non stopped download speed, we can affirm that 4.8 megabytes were download per minute (28.8 / 6 = 4.8). As after 2 minutes, there were 38.4 megabytes left, in order to know the size of the file we have to do the following calculation:

38.4 + (4.8 x 2) = Size of the file

38.4 + 9.6 = 48 megabytes

The size of the file is of 48 megabytes.

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Decide whether the table shows a proportional relationship between x and y.

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Write an expression for the perimeter of the house use the work you completed in parts A and B to guide you (the numbers in the

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The total length of Valerie’s walls is (2.5 × 4) + (21.25 × 3) + 32.

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3 years ago

Jace is a songwriter who collects royalties in his songs whenever they are played in a commercial or a movie. Jace will earn $50

VashaNatasha [74]

Jace's song were played on 8 commercials and 2 movies

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

<em>Elimination Method</em>
<em>Substitution Method</em>
<em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

<em>Let:</em>

<em>Number of Commercials = C</em>

<em>Number of Movies = M</em>

$\texttt{ }$

<em>Jaces songs were played on 6 more commercials than movies.</em>

$\boxed{C = 6 + M}$ → <em>Equation 1</em>

$\texttt{ }$

<em>Jace will earn $50 every time one of his songs is played in a commercial and he will earn $140 every time one of his songs is played in a movie.</em>

<em>His total earnings in the royalties from all commercials and movies was $680.</em>

$\boxed{50C + 140M = 680}$ → <em>Equation 2</em>

$\texttt{ }$

<em>Equation 1 ↔ Equation 2 :</em>

$50C + 140M = 680$

$50 ( 6 + M ) + 140M = 680$

$300 + 50M + 140M = 680$

$190M = 680 - 300$

$190M = 380$

$M = 380 \div 190$

$M = 2$

$\texttt{ }$

$C = 6 + M$

$C = 6 + 2$

$C = 8$

$\texttt{ }$

<h2>Conclusion:</h2>

The number of commercials and the number of movies in which Jaces songs where played is respectively 8 and 2

$\texttt{ }$

<h3>Learn more</h3>

Perimeter of Rectangle : brainly.com/question/12826246
Elimination Method : brainly.com/question/11233927
Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

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3 years ago

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Check the picture below.

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now, we could check for the CA distance, however, we already know that AB ≠ BC, so there's no need.

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3 years ago

A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021

egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

$\displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}$

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

$\displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}$

Therefore, for the last term we have;

$\displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}$

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

$\displaystyle \frac{A}{2} = \mathbf{ 1011 \cdot \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460} \right)}$

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2} +\frac{1}{2} - \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022} \right)$

Which gives;

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2022} \right)$

$\displaystyle A = 2 \times 1011 \cdot \left(1 - \frac{1}{2022} \right) = \frac{1032231}{511} \approx \mathbf{2020.022}$

A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0

2 years ago

Read 2 more answers