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marshall27 [118]
3 years ago
7

The votes for president in a club election were: Smith: 24 Munoz: 32 Park: 20 Find the following ratios and write in simplest fo

rm. Votes for Munoz to Smith: Votes for Park to Munoz: Votes for Smith to total votes: Votes for Smith to Munoz to Park:
Mathematics
1 answer:
Setler79 [48]3 years ago
4 0

Answer:

Step-by-step explanation:

Smith=24

Munoz=32

Park=20

Total votes=24+32+20=76

Ratio of votes for Munoz to Smith

32:24

=4:3

Ratio of votes for Park to Munoz

20:32

=5:8

Ratio of votes for Smith to total votes

24:76

=6:19

Ratio of votes for Smith to Munoz to Park

24:32:20

=6:8:5

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4a - 5 = 11<br> Solve this please
d1i1m1o1n [39]

Answer:

a = 4

Step-by-step explanation:

Given equation:

4a - 5 = 11

Add 5 to both sides:

⇒ 4a - 5 + 5 = 11 + 5

⇒ 4a = 16

Divide both sides by 4:

⇒ 4a ÷ 4 = 16 ÷ 4

⇒ a = 4

7 0
2 years ago
Read 2 more answers
Since a math school opened the girls basketball team had the same record every season the team won a total of 182 games while lo
Tems11 [23]

Answer:

11

Step-by-step explanation:

I guess

6 0
3 years ago
Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

5 0
2 years ago
Will give brainliest.
Dennis_Churaev [7]
Pretty sure it's A. (X times .5 equals Y)
8 0
3 years ago
Which represents a side length of a square that has an area of 450 square inches?
amm1812

The formula of an area of a square:


A=a^2


a - a side


We have A=450\ in^2


substitute:


a^2=450\to a=\sqrt{450}\\\\a=\sqrt{225\cdot2}\\\\a=\sqrt{225}\cdot\sqrt2\\\\\boxed{a=15\sqrt2\ in}


Used:

\sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}

5 0
3 years ago
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