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gayaneshka [121]
3 years ago
9

What is an equation for the line that passes through points (5, -5) and (3, 7)?

Mathematics
1 answer:
Alchen [17]3 years ago
3 0

 

\displaystyle\bf\\\frac{x-3}{5-3}=\frac{y-7}{-5-7}\\\\\\\frac{x-3}{2}=\frac{y-7}{-12}\\\\\\-12(x-3)=2(y-7)\\\\-12x+36=2y-14\\\\-12x-2y+36+14=0\\\\-12x-2y+50=0~~\Big|:(-2)\\\\\boxed{\bf6x+y-25=0}

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Use technology or a z-score table to answer the question.
Drupady [299]

Answer:

C

Step-by-step explanation:

Finding the z-score:

z = (x - μ) / σ

z = (66 - 57) / 9

z = 1

Using a z-score table or calculator:

P(z < 1) = 0.8413

84.13% of 4000 is:

0.8413 (4000) = 3365.2

Rounding up to the nearest whole number, approximately 3366 students will score less than 66.  Answer C.

8 0
3 years ago
-3(7w-3)+8w=-5(w+1) what is the value of w
bogdanovich [222]

Answer:

2

Step-by-step explanation:

Step 1:

- 21w + 9 + 8w = - 5w - 5

Step 2:

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Step 3:

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Step 4:

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Step 5:

14 = 7w

Answer:

w = 2

Hope This Helps :)

6 0
3 years ago
) Elise has put 5 cans (all of the same size) on her kitchen counter; 2 cans of vegetables, 2 cans of soup , and 1 can of peache
Anvisha [2.4K]

Answer:

0.7 = 70%.

Step-by-step explanation:

There are 5 cans, and she will pick 2, so the number of possibilities that she can pick 2 cans is a combination of 5 choose 2:

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To find how many possibilities there are with at least 1 can of soup, we can find the number of groups that include no cans of soup, and then see how many possibilities complete the total 10:

There are 3 "no-soup" cans, so the number of possibilities is a combination of 3 choose 2:

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So, there are 3 possibilities that have no cans of soup, so the number of possibilities that have at least 1 can of soup is 10 - 3 = 7

Then, the probability is 7 / 10 = 0.7 = 70%.

4 0
3 years ago
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Ierofanga [76]
The answer its 16 real easy btw
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3 years ago
Michael has 5 boxes. There are 5kg of apples in each box. When empty, a box weighs 5-2 kg.
Sphinxa [80]
As I understand from the given above, each box when empty weighs 5-2 kg or 3 kg. To determine the total weight of Michael's boxes when empty, we just have to multiply 3 kg by 5. This gives us an answer of 15 kg. Thus, the total mass of Michael's boxes is 15 kg. 
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3 years ago
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