Answer:
ab(ab + 20)
Step-by-step explanation:
Because we see both terms have at least one ab in it, we can factor out ab and get ab(ab + 20). However, because ab^2 does not have any coefficient, there is nothing more to factor out. Thus, ab is your greatest common factor, or GCF.
The ratio which could represent the number of large containers of milk to small containers of milk in an order from the grocery store is 0.56:1.
Given that a grocery store orders 4 large containers of milk for every 7 small containers of milk.
We are required to find the ratio that represent the number of large containers of milk to small containers of milk in an order from the grocery store.
Ratio is basically the quantity represent in terms of other quantity.
Ratio=Number of large containers:Number of small containers
=4:7
Divide by 7.
=4/7:1
=0.56:1
Hence the ratio which could represent the number of large containers of milk to small containers of milk in an order from the grocery store is 0.56:1.
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Answer:
At first, we divide the parallelogram into two triangles by joining any two opposite vertices. These two triangles are exactly the same (congruent) and thus have equal areas. The area of the parallelogram is the summation of the individual areas of the two triangles. We drop a perpendicular from a vertex to its opposite side to get an expression for the height of the triangles. The area of the individual triangle is 12×base×height12×base×height .The area of the parallelogram being twice the area of the triangle, thus becomes after evaluation base×heightbase×height .
Complete step by step answer:
The parallelogram can be divided into two triangles by constructing a diagonal by joining any two opposite vertices.


In the above figure, ΔABDΔABD and ΔBCDΔBCDare the two such triangles. These two triangles have:
AB=CDAB=CD (as opposite sides of a parallelogram are equal)
AD=BCAD=BC (opposite sides of a parallelogram are equal)
BDBD is common
Thus, the two triangles are congruent to each other by SSS axiom of congruence. Since, the areas of two congruent triangles are equal,
⇒area(ΔABD)=area(ΔBCD)⇒area(ΔABD)=area(ΔBCD)
Now, we need to find the area of ΔABDΔABD . We draw a perpendicular from DD to the side ABAB and name it as DEDE . Thus, ΔABDΔABD is now a triangle with base ABAB and height DEDE .
Then, the area of the ΔABD
