Answer: 0.137 m/s
Explanation:
from the question we are given the following
mass of train A (Ma) = 150,000 kg
velocity of train A (Va) = 0.3 m/s
mass of train B (Mb) = 95,000 kg
velocity of train B (Vb) = -0.12 m/s
final velocity (V) = ?
mass of both trains = 245,000 kg
- to solve this question we apply the conservation of momentum
MaVa + MbVb = (Ma + Mb) x V
V = (MaVa + MbVb) / (Ma + Mb)
V = ((150,000 x 0.3) + (95,000 x (-0.12))) / (245,000)
V = -33600 / 245,000
V = 0.137 m/s
Answer:
C
It is C i have to type this because i need 20 characters.
<span>The jump from 1966 to 16347 is the largest one or simply we can say it is hard to lose the 3rd electron.Whereas, it is relatively easy to lose the first two electrons.
So there will be only 2 electrons in the outer most shell.
According to the information mentioned above we can conclude the </span><span>unknown element likely belongs to the second group.
</span><span>I2 = 1752 kj/mol</span>
