All categories

4 years ago

Why do we need to use telescopes that are sensitive to other types of radiation

Physics

1 answer:

IrinaVladis [17]4 years ago

5 0

Answer:

Astronomers use the variety of telescopes which are sensitive to different parts of electromagnetic spectrum. So they have different telescopes or detectors for each band of the spectrum. In order to study the objects in space they study it through various portions of EM waves.Here we take an example of the microwaves. Our earth's atmosphere block most of the microwaves. So Scientists use the telescopes on satellites to study these cosmic waves. Microwaves are the remains of big bang so by studying them we can describe the beginning of universe.

Explanation:

You might be interested in

State one effect of increase in heat for a temperature range of 50°C to 100°C<br> on Plastic

natima [27]

Answer:

why is fraction called a necessary evil

6 0

3 years ago

Which most likely could cause acceleration?

Anastaziya [24]

Answer:

this may seem wierd but a hill

Explanation:

a hill if its steep enough and you have wings on a car or something could make you fly depending the weight wind would also help a stop light no a flat road could if you going fast enough wat movement is depending thiers your 4 options hopee you learned something

8 0

3 years ago

A particle is leaving the Moon in a direction that is radially outward from both the Moon and Earth.

Misha Larkins [42]

Answer:

$2780m/s$

Explanation:

Essentially, Kinetic energy of the particle must equal the combined potential energies of earth and the moon when the object is on the moon's surface, meaning the full equation is

$M_E$ =Mass of Earth= $5.97*10^2^4$

$M_m$ =Mass of Moon= $7.4*10^2^2kg$

$r_E$ =distance from earth's center to the moon's= $3.84*10^8m$

$r_m$ =radius of moon= $1.738*10^6m$

After some algebra, the equation simplifies to

$v=\sqrt{2G*(\frac{M_E}{r_E+r_m}+\frac{M_m}{r_m})}$

Plugging in the values of G, which is $6.67*10^-^1^1 \frac{m^3}{kg*s^2}$ , should yield the proper answer of 2780m/s.

4 0

3 years ago

A rocket blasts off vertically from rest on the launch pad with an upward acceleration of 2.90 m/s2 . At 20.0s after blastoff, t

Brilliant_brown [7]

Answer:

A) 580m

B) 0 m/s

C) 9.8m/s^2

D) downward

E) 10.87s

F) 106.62 m/s

Explanation:

A) The distance traveled by the rocket is calculated by using the following expression:

$y=\frac{1}{2}at^2$

a: acceleration of the rocket = 2.90 m/s^2

t: time of the flight = 20.0 s

$y=\frac{1}{2}(2.90\frac{m}{s^2})(20.0s)^2=580m$

B) In the highest point the rocket has a velocity with magnitude zero v = 0m/s because there the rocket stops.

C) The engines of the rocket suddenly fails in the highest point. There, the acceleration of the rocket is due to the gravitational force, that is 9.8 m/s^2

D) The acceleration points downward

E) The time the rocket takes to return to the ground is given by:

$t=\sqrt{\frac{2y}{g}}=\sqrt{\frac{2(580m)}{9.8m/s^2}}=10.87s$