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ss7ja [257]
3 years ago
12

Which is the formula to calculate the slope of this line? A mass divided by volume B mass minus volume C volume divided by mass

D volume minus mass

Physics
1 answer:
Hatshy [7]3 years ago
3 0

A- mass divided by volume

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Convertir 500 f a grado celsios
Allushta [10]

Answer:

260° C

Explanation:

si

5 0
3 years ago
Read 2 more answers
the speed of a train is decreased in a uniform rate from 96 km/h to 48km/h through a distance of 800m. calculate the distance co
GREYUIT [131]

Answer:

1066.67 m

Explanation:

Given:

v₀ = 96 km/h = 26.67 m/s

v = 48 km/h = 13.33 m/s

Δx = 800 m

Find: a

v² = v₀² + 2aΔx

(13.33 m/s)² = (26.67 m/s)² + 2a (800 m)

a = -0.333 m/s²

Given:

v₀ = 26.67 m/s

v = 0 m/s

a = -0.333 m/s²

Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (26.67 m/s)² + 2 (-0.333 m/s²) Δx

Δx = 1066.67 m

Round as needed.

7 0
3 years ago
Are particularly useful in explaining deformation and strengthening in metallic materials.
vampirchik [111]

Answer: value

Explanation:

8 0
4 years ago
The severity of a fall depends on your speed when you strike the ground. All factors but the acceleration from gravity being the
Diano4ka-milaya [45]

Answer:

<em>The object could fall from six times the original height and still be safe</em>

Explanation:

<u>Free Falling</u>

When an object is released from rest in free air (no friction), the motion is completely dependant on the acceleration of gravity g.

If we drop an object of mass m near the Earth surface from a height h, it has initial mechanical energy of

U=m.g.h

When the object strikes the ground, all the mechanical energy (only potential energy) becomes into kinetic energy

\displaystyle K=\frac{1}{2}m.v^2

Where v is the speed just before hitting the ground

If we know the speed v is safe for the integrity of the object, then we can know the height it was dropped from

\displaystyle m.g.h=\frac{1}{2}m.v^2

Solving for h

\displaystyle h=\frac{m.v^2}{2mg}=\frac{v^2}{2g}

If the drop had occurred in the Moon, then

\displaystyle h_M=\frac{v_M^2}{2g_M}

Where hM, vM and gM are the corresponding parameters on the Moon. We know v is the safe hitting speed and the gravitational acceleration on the Moon is g_M=1/6 g

\displaystyle h_M=\frac{v^2}{2\frac{1}{6}g}

\displaystyle h_M=6\frac{v^2}{2g}=6h

This means the object could fall from six times the original height and still be safe

6 0
3 years ago
Which of the following describes one of the main features of wave-particle duality?
steposvetlana [31]
<h2>Answer:  as mass increases, the wave nature of matter is less easy to observe.</h2>

At the beginning of the 20th century the French physicist Louis De Broglie proposed the existence of matter waves, that is to say that <u>all matter has a wave associated with it.</u>

In this sense, the de Broglie wavelength \lambda is given by the following formula:

\lambda=\frac{h}{p}   (1)

Where:

h is the Planck constant

p is the momentum of the atom, which is given by:

p=m.v (2)

Where:

m is the mass

v is the velocity

Substituting (2) in (1):

\lambda=\frac{h}{m.v}[\tex]   (3)As we can see, if we increase the mass, the wavelength decreases (because [tex]\lambda is inversely proportional to m).

Therefore, if the wavelength decreases the wave nature of matter is less easy to observe.

The other options are incorrect because:

a) as v increases \lambda decreases and the particle nature matter becomes more evident

b) as p decreases \lambda increases and the wave nature matter becomes more evident

c) There is also a relation between the wavelength and the energy E:

\lambda=\frac{hc}{E}

So, as energy increases, the particle nature matter becomes more evident and the wave nature of matter becomes harder to observe

8 0
3 years ago
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