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sasho [114]
3 years ago
11

Can someone help me with these questions? ty!

Mathematics
1 answer:
lesya [120]3 years ago
4 0

Answer:

2. 4 email per min

3. a bottle of milk cost 4.76

5. economy

6. economy

7b. $1.00 per oz

8b. $75 per room

8c. 16 rooms

Step-by-step explanation:


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Y=(x-5)(x+1). What is the vertex of the parabola
dedylja [7]

Answer:

Rewrite in vertex form and use this form to find the vertex  

(h , k ) .  ( 2 , − 9 )

5 0
3 years ago
If the width of something is 5m and the perimeter is 22m, what is the length and area
Nadusha1986 [10]
I assume that this 'something' has a rectangular shape. If its width is 5m, than the length of two sides is 2 * 5 = 10m. Now if the perimeter is 22 square meters, then the lenght of another two sides is 12 / 2 = 6.

12 because 22 (the perimeter) - 10 (lenght of the 2 sides) = 12 (length of another 2 sides).
4 0
3 years ago
In the diagram below secants PT & PU have been drawn from exterior point P such that the four arcs intercepted have the foll
fiasKO [112]

Answer:

  • x = 30°
  • RS = 30°, SR = TU = 120°, UR = 90°
  • ∠P = 45°
  • ∠UTS = 60°

Step-by-step explanation:

(a) If RS = x, then the sum of arcs around the circle is ...

  x + 4x +4x +3x = 360°

  12x = 360°

  x = 30°

__

(b) Based on the given ratios, the arc measures are computed from x. For example, ST = TU = 4x = 4(30°) = 120°

  • RS = 30°
  • ST = 120°
  • TU = 120°
  • UR = 90°

__

(c) Angle P is half the difference of arcs TU and RS:

  ∠P = (TU -RS)/2 = (120° -30°)/2

  ∠P = 45°

__

(d) Inscribed angle UTS is half the measure of the arc it intercepts. Arc RU has the measure (30° +90°) = 120°, so the measure of UTS is ...

  ∠UTS = 120°/2 = 60°

4 0
4 years ago
Could someone help me out for number 5 please?
kifflom [539]

Answer:

she didnt multiply 5 times 12

7 0
4 years ago
Find the sum of the series given in sigma notation.
Kryger [21]

Answer:

Option b is correct 175

Step-by-step explanation:

n = 7

k = 6

3k -2 ------1

put k = 6 in above eq. for finding first term

  a1 = 3(6) - 2  = 18 - 2 = 16

put k = 7 in above eq. for finding first term

 a2 = 3(7) - 2 = 21 - 2 = 19

 a3 = 3 (8) - 2 = 24 - 2 = 22

16, 19 , 22, ...  //Arithmetic series formation

a1 = 16 , a2 = 19

d = a2 - a1 = 19 - 16 = 3 //Difference of first two terms

Using sum forumula for arithmetic series

sum = \frac{n}{2}(2a1 + (n-1)d)

      = \frac{7}{2}(2a1 + (7-1)d)

      = \frac{7}{2}(2(16) + (6)3)

      =  \frac{7}{2}(32 + 18)    

      =  \frac{7}{2}(50)

      = 7 * 25

      = 175




4 0
3 years ago
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