Anybody please ?????

In a class of 25 students, 24 of them took an exam in class and 1 student took a make-up exam the following day. The professor g

gavmur [86]

Answer:

The value is $\mu_n = 73.6$

Step-by-step explanation:

From the question we are told that

The total number of students is $N = 25$

The number of student that took exam in class is n = 24

The number that took make up exam is k = 1

The average score of the first 24 students is $\mu = 74$

The standard deviation is $\sigma = 8.9$

The average score of the student who took make up test is $\= x = 64$

Generally the new average is mathematically represented as

$\mu_n = \frac{( n * \mu ) + \= x }{N}$

$\mu_n = \frac{( 24 * 74 ) + 64 }{25}$

$\mu_n = 73.6$

7 0

2 years ago

Slove for fg -9h= 10j to get g by itself

Afina-wow [57]

Simplifying fg + -9n = 10j Solving fg + -9n = 10j Solving for variable 'f'. Move all terms containing f to the left, all other terms to the right. Add '9n' to each side of the equation. fg + -9n + 9n = 10j + 9n Combine like terms: -9n + 9n = 0 fg + 0 = 10j + 9n fg = 10j + 9n Divide each side by 'g'. f = 10g-1j + 9g-1n Simplifying f = 10g-1j + 9g-1n

7 0

3 years ago

At Clucker's Chicken, a bucket of 4 pieces of dark meat and 5 pieces of white meat costs 7.05. A bucket of 3 pieces of dark meat

Alenkinab [10]

Answer:

The cost of a piece of dark meat is $0.70 and the cost of a piece of white meat is $0.85.

Step-by-step explanation:

Given:

At Clucker's Chicken, a bucket of 4 pieces of dark meat and 5 pieces of white meat costs 7.05.

A bucket of 3 pieces of dark meat and 8 pieces of white meat costs 8.90.

Now, to find the cost of a piece of dark meat and the cost of a piece of white meat.

Let the cost of a piece of dark meat be $x.$

And the cost of a piece of white meat be $y.$

A bucket of 4 pieces of dark meat and 5 pieces of white meat costs $7.05.

So,

$4x+5y=7.05$

$4x=7.05-5y$

$x=\frac{7.05-5y}{4}$ .......(1)

Now, a bucket of 3 pieces of dark meat and 8 pieces of white meat costs $8.90.

$3x+8y=8.90$

Substituting the value of $x$ from equation (1) we get:

$3(\frac{7.05-5y}{4})+8y=8.90$

$\frac{21.15-15y}{4} +8y=8.90$

$\frac{21.15-15y+32y}{4} =8.90$

Multiplying both sides by 4 we get:

$21.15-15y+32y=35.60$

$21.15+17y=35.60$

Subtracting both sides by 21.15 we get:

$17y=14.45$

Dividing both sides by 17 we get:

$y=0.85$

The cost of a piece of white meat = $0.85.

Now, substituting the value of $y$ in equation (1) we get:

$x=\frac{7.05-5y}{4}$

$x=\frac{7.05-5\times 0.85}{4}$

$x=\frac{7.05-4.25}{4}$

$x=\frac{2.8}{4}$

$x=0.70.$

The cost of a piece of dark meat = $0.70.

Therefore, the cost of a piece of dark meat is $0.70 and the cost of a piece of white meat is $0.85.

5 0

3 years ago

Roger made $25 profit on the stamp collection costing him $125. What was his profit as a percentage of the cost price?

SVETLANKA909090 [29]

STEP-BY-STEP SOLUTION:

Profit = $25

Cost = $125

Profit as a % of the cost price

= ( 25 / 125 ) × 100%

= ( 1 / 5 ) × 100%

= 20%

ANSWER: 20%

3 0

3 years ago

Read 2 more answers

What is the distance between points D and H?

Maslowich

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ D(\stackrel{x_1}{9}~,~\stackrel{y_1}{8})\qquad H(\stackrel{x_2}{1}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ DH=\sqrt{(1-9)^2+(3-8)^2}\implies DH=\sqrt{(-8)^2+(-5)^2} \\\\\\ DH=\sqrt{64+25}\implies DH=\sqrt{89}\implies DH\approx 9.4$

8 0

3 years ago