To solve this problem you must apply the proccedure shown below:
1. You have that the baby pool holds 
and the medium pool measures three times the height and width of the baby pool and both have the shape of a cylinder. Then, you can use the formula for calculate the volume of a cylinder, which is:
Where 
is the radius (the half of the width), and 
is the height.
2. As the height and the width of the medium pool measure three times the height and width of the baby pool, you must multiply the radius and the heigh by 
, therefore, the volume of the medium pool (
) is :
The answer is: B. 
Use the quadratic formula with a = 2, b = -5, and c = 1
x = -b ± sq rt b2 - 4ac
-------------------- <---------- Please note: sq rt is over entire expression of b^2 - 4ac
2a
x = - (-5) ± sq rt (-5)2 + 4(2)(1)
-------------------------------- <---------Please note: sq rt is over entire expression (-5)2 + 4(2)(1)
2(2)
x = 5 ± √17
---------
4
x = 5 + 1√17 OR x = 5 + -1√17
--- --- --- ----
4 4 4 4
Answer: x = 5 + 1√17 OR x = 5 + -1√17
--- -- -- --
4 4 4 4
Hey!!
here is your answer >>>
As we know, The formula for the length of a trinagle is
(1/2)(base)(height) !.
Height is 6/5 and area is 2/5, then what is the base, we will just have to substitute these values!.
which is ,
2/5 = (1/2)(base)(6/5)
2/5 = (base)(3/5)
base = (2/5)/(3/5)
base = (2/5)(5/3)
base = 2/3 ft!.
Hope my answer helps!
The greatest common factor is 6
36: 1, 2, 3, 4, 6, 9, 12, 18, 36
42: 1, 2, 3, 6, 7, 14, 21, 42
Hope this helps : )
9514 1404 393
Answer:
2) x = 7
3) x = 5
Step-by-step explanation:
When a transversal crosses parallel lines, all of the acute angles are congruent, and all of the obtuse angles are congruent. When it crosses at right angle, all of the angles are right angles.
2) All of the angles are right angles.
11x +13 = 90
11x = 77 . . . . . . subtract 13
x = 7 . . . . . . . divide by 11
__
3) The two marked angles are acute.
16x = 80 . . . . the acute angles are congruent
x = 5 . . . . . . divide by 16
