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KengaRu [80]
3 years ago
9

victoria has 100 trading cards. every month she buys 10 more cards. will she have 160 cards in four months?

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
8 0

Answer:

No, in 4 months she will have 140 cards.

Step-by-step explanation:

If Victoria has 100 cards now, and adds 10 cards every month, she will have added 40 cards in 4 months.

10 x 4 = 40

40 + 100  = 140

sveta [45]3 years ago
4 0

Answer:

No, she will have 140 cards in 4 months

Step-by-step explanation:

the equations is:

f(x) = 100 + 10x

now x = 4

f(4) = 100 + 10(4)

f(4) = 100 + 40

f(4) = 140

140 does not = 60

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Given segments AB and CD intersect at E.
nata0808 [166]

The length of a segment is the distance between its endpoints.

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<u>(a) Length of AB</u>

We have:

\mathbf{A = (1,2)}

\mathbf{B = (4,5)}

The length of AB is calculated using the following distance formula

\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}

\mathbf{AB = \sqrt{18}}

Simplify

\mathbf{AB = 3\sqrt{2}}

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First, we calculate the length of CD using:

\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

Where:

\mathbf{C = (2, 4)}

\mathbf{D = (2, 1)}

So, we have:

\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}

\mathbf{CD = \sqrt{9}}

\mathbf{CD = 3}

By comparison

\mathbf{CD \ne AB}

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

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\mathbf{AB = \frac 12 \times CD}

The above equation is not true, because:

\mathbf{3\sqrt 2 \ne \frac 12 \times 3}

Hence, AB does not bisect CD

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If CD bisects AB, then:

\mathbf{CD = \frac 12 \times AB}

The above equation is not true, because:

\mathbf{3 \ne \frac 12 \times 3\sqrt 2}

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0
3 years ago
Write a quadratic equation with 0, -8
Ludmilka [50]
If 0, and -8 are the roots of the quadratic equation we can write
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