Answer:
3,466.32
Step-by-step explanation:
Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is 
Hence, the average of the shortest distance of B from each side is 22 m
Learn more about average here-
brainly.com/question/24057012
#SPJ10
here we have 3X to 5 seventh power in radical form

we need write this in radical form we knwo that 
so ![3x^{5/7} =\sqrt[7]{3x^{5}}](https://tex.z-dn.net/?f=%203x%5E%7B5%2F7%7D%20%3D%5Csqrt%5B7%5D%7B3x%5E%7B5%7D%7D%20%20%20)
this will be the radical form .
Answer:
(A) x=40
Step-by-step explanation:
Given: It is given that m is parallel to n.
To find: The value of x.
Proof: It is given that m is parallel to n, from the figure it can be seen that 105° and (3x-15)° forms alternate exterior angles which are equal in measure because m is parallel to n.
Thus, 
⇒
⇒
⇒
⇒
Thus, the value of x is 40, hence option A is correct.
Hello there.
<span>Which numbers are necessary to solve this problem?
Brian goes to the gym 3 times a week. He exercises for 45 minutes each visit. Fifteen of those minutes are spent on weights and the rest are spent on the treadmill.
How much time does Brian spend on the treadmill in 4 weeks?
Answer: </span><span>3 times a week, 45 minutes, 15 minutes, 4 weeks
</span>