Answer:
6 nights with 4 logs left over
The greatest common factor is the biggest number taken from the values.
Q1. The answer is <span>A. 5y^6
</span>

Since

, then

Back to our expression:

The greatest common factor is thus

Q2. The answer is <span>D. 12xy^2
</span>

We will use the rule

to factorise the exponents:

The greatest common factor is thus
To calculate how much 9 apples cost, you must multiply 9 to 4.55 and then divide by 7. This is done by setting up a proportion.
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