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OLga [1]
3 years ago
5

Belinda's family goes through 572 gallons of milk in a year. How many gallons of milk does her family drink every week? (There a

re 52 weeks in a year.)
Mathematics
1 answer:
Novay_Z [31]3 years ago
3 0

572 gallons of milk / 52 weeks = 11 gallons of milk / week.

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What other information do you need in order to prove the triangles congruent using the SAS congruence postulate?
ziro4ka [17]

Answer:

I think D

Step-by-step explanation:

I think that the answer is D, since the angles are not visibly shown to be equal. If you knew answer D, you would then be able to see that segments BC and CD are congruent. I am not 100% sure, however.

4 0
3 years ago
What is the difference? −43−(−18) Enter your answer in the box.
gulaghasi [49]

Hello!

Answer:

-25

Step-by-step explanation:

−43+18

−25

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3 years ago
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The value of the digit 5 in 25,513 is how many times the value of the digit 5 in 357
SOVA2 [1]

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4 years ago
Let f(x)=2x^2+7x-5 and g(x)=-8x^2-3x+5 what is g(x)+f(x)
ser-zykov [4K]
F(x) = 2x² + 7x - 5
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The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
Kruka [31]

Answer:

6.76-2.01\frac{2.55}{\sqrt{50}}=6.03    

6.76+2.01\frac{2.55}{\sqrt{50}}=7.49    

The 95% confidence interval would be given by (6.03;7.49)    

Step-by-step explanation:

Notation

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n=50 represent the sample size  

Solution

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

We can calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=6.76

The sample deviation calculated s=2.55

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=50-1=49

We assume a standard confidence level of 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that t_{\alpha/2}=2.01

Now we have everything in order to replace into formula (1):

6.76-2.01\frac{2.55}{\sqrt{50}}=6.03    

6.76+2.01\frac{2.55}{\sqrt{50}}=7.49    

The 95% confidence interval would be given by (6.03;7.49)    

3 0
4 years ago
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