<span>(2^1/2x2^3/4)^2
</span><span> ((2^1/2)(2^3/4))^2
</span> ((2^1/2)^2)((2^3/4)^2)
(2)(2^3/2)
(4*2^3)^(1/2)
(2*2*2^3)^(1/2)
(*2^5/2)
The answer for this case is
b. <span>sqrt 2^5</span>
Answer:
plot your first point at (-3,5) then down 2 units and to the right 5 units
Step-by-step explanation:
Answer:
4+3n
Step-by-step explanation:
We get the formula 4+3n because the pattern is +3 each term starting with the first term as 7. Since the first term is 7, we get 4+3n.
Answer:
simple
Step-by-step explanation:
t=b×h/2 and p= b×h
The number must be be 67 and 113. It must be a multiple of 3, 6, AND 9. For instance, 18 is a multiple of 3, 6, and 9. 3*6 is 18, 6*3 is 18, and 9*2 is 18.
The answer is: 72, 90, 108
These are all multiples of 3, 6, and 9. 3*24, 12*6, and 9*8 is 72. 3*30, 6*15, and 9*10 is 90. 6*36, 6*18, and 9*12 is 108.
