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fgiga [73]
3 years ago
12

Time spent using e-mail per session is normally distributed with a mean = to 8 minutes and standard deviation = 2minutes. If a r

andom samples of 36 sessions were selected, the computed sample standard deviation would be
a. 0.25
b. 0.3333
c. 0.42
d. 0.48
Mathematics
1 answer:
den301095 [7]3 years ago
6 0

Answer:

The correct option is (b) 0.3333.

Step-by-step explanation:

The standard deviation of the sampling distribution of sample mean (\bar x) is known as the standard error (\sigma_{\bar x}).

The standard error is given as follows:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=8\\\\\sigma=2\\\\n=36

Compute the standard deviation of the sample mean as follows:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

    =\frac{2}{\sqrt{36}}\\\\=\frac{2}{6}\\\\=\frac{1}{3}\\\\=0.3333

Thus, the standard deviation of the sample mean is 0.3333.

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