Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
Answer:
(- 3/13, 56/13)
Step-by-step explanation:
See steps below:)
Answer:
Combine the terms with the same variable
Step-by-step explanation: so 9x-4x+9x-4x
Answer:
1.59
Step-by-step explanation:
Divide 2,787 by 1,750
