Answer:
1
Step-by-step explanation:
There are about 110,000 days in 300 years, so the expected number of failures is about 10/11 ≈ 1.
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This assumes the launch conditions are identical for each of the launches, or that whatever variation there might be has no effect on the probability. These are bad assumptions.
The answer to this question is (-2,0)
Answer:
No.
Step-by-step explanation:
Both sets contain the elements k and m.
Answer:
28x^2+3x-18
Step-by-step explanation:
Formula: (a+b)(a+b) = a^2 + a*b + a*b + b*b
Following this: 28x^2 -21x +24x -18
Then you combine like terms: 28^2 +3x-18
hope this helped!! :)
Ok so
what we do is
how much greater=wasted space=cylindervolume-conevolume
volume of a cinlinder=hpir^2
volume of a cone=(1/3)hpir^2
we can alread sybsitute something
(3/3)hpir^2-(1/3)hpir^2=(2/3)hpir^2
so wasted space=(2/3)hpir^2
diameter=4
d=2r
d/2=r
4/2=2=r
and 6=height
so
2/3(6)(3.14)(2^2)
4(3.14)(4)
16(3.14)
50.24 in^3 wasted
