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Naya [18.7K]
3 years ago
5

Solve for x 2x < 2/3 (4x +4)

Mathematics
1 answer:
Verizon [17]3 years ago
6 0

Answer:

x>−4

Step-by-step explanation:

i hope this helps you

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the vertices of ABC are points A(1,1), B(4,1), and C(4,5). find the cosines of the angles of the triangle.
pickupchik [31]

Answer:

  • cos(A) = 3/5
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Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relation between the cosine of an angle and the sides of the triangle.

  Cos = Adjacent/Hypotenuse

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<h3>Angle A</h3>

In the given triangle, the hypotenuse is AC. The side adjacent to angle A is AB, so its cosine is ...

  cos(A) = AB/AC

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<h3>Angle B</h3>

The right angle in the triangle is angle B. The cosine of a right angle is 0.

  cos(B) = 0

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<h3>Angle C</h3>

The side adjacent to angle C is CB, so its cosine is ...

  cos(C) = CB/AC

  cos(C) = 4/5

7 0
2 years ago
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Solve the simultaneous equations using elimination method.<br>4x – 3y = 1<br>x + 3y =​
babymother [125]

Answer:

x=\frac{1}{5}

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Step-by-step explanation:

4x - 3y = 1

x + 3y = 0

Req To Solve With Elimination:

Make Them Equal:

-> 4x - 3y = 1

-> 4x + 4 . 3y = 0

Simplify:

->  4x - 3y = 1

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-> 4x - 4x - 3y - 12y = 1

-> -3y - 12y = 1

-> -15y = 1

-> y = -\frac{1}{15}

-> x+3(-\frac{1}{15} )=0

-> x -\frac{1}{5}=0\\

-> x=\frac{1}{5}

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3 years ago
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