Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
Answer: 34
Step-by-step explanation:
<u>Given expression</u>
[3 - (3 · 3) + 33 ÷ 3] × 4 · 5 / 10 - 2 · 3
<u>Simplify by parentheses in the bracket</u>
=[3 - 9 + 33 ÷ 3] × 4 · 5 / 10 - 2 · 3
<u>Simplify by multiplication</u>
=[3 - 9 + 33 ÷ 3] × 20 / 10 - 6
<u>Simplify by division</u>
=[3 - 9 + 11] × 10 - 6
<u>Simplify by bracket (addition/subtraction)</u>
=[-6 + 11] × 10 - 6
=[4] × 10 - 6
<u>Simplify by multiplication</u>
=40 - 6
<u>Simplify by subtraction</u>
=
Hope this helps!! :)
Please let me know if you have any questions
Answer:
The angle in C
Step-by-step explanation:
Answer:
15
Step-by-step explanation: