Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Answer:
3(x +3)
Step-by-step explanation:
factored by grouping
Answer:
Step-by-step explanation:
37 is prime, so it's not possible to reduce/simplify 37/80. 37/80 is the ratio of two integers. We could, of course, use a calculator to find the decimal equivalent: 0.4625, but this is not more accurate than the ratio 37/80.
Answer:
Step-by-step explanation:
You draw a line right down the middle so it makes it to equal triangle
