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klasskru [66]
3 years ago
11

The equation x+(75.3−x)=75.3 represents the sum of two angles. How many possible combinations of angle measures satisfy these co

nditions? Please Help!!
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

Answer:

smaller angle = x

larger angle = 3x + 8

x + 3x + 8 = 180

4x + 8 = 180

4x = 172

x = 43

The smaller angle measures 43 degrees.

The larger angle measures 137 degrees.

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Use four rectangles to estimate the area between the graph of the function f(x) = V3x + 5 and the x-axis on the interval[0, 4] u
yuradex [85]

Answer:

  12.123

Step-by-step explanation:

You want the area under the curve f(x) = √(3x+5) on the interval [0, 4] estimated using the left sum and four subintervals.

<h3>Riemann sum</h3>

When the interval [0, 4] is divided into four equal parts, each has unit width. That means the area of the rectangle defined by the curve and the interval width will be equal to the value of the curve at the left end of the interval.

The area we want is the sum ...

  f(0) +f(1) +f(2) +f(3)

As the attachment shows, that sum is ...

  area ≈ 12.123 . . . square units

__

<em>Additional comment</em>

The table values in the attachment are rounded to 7 decimal places. Trailing zeros are not shown. Actual values used have 12 significant digits, as the total shows.

Such a sum is called a Riemann sum, named for a German mathematician. Four such sums are commonly used, and further refinements are possible. Those are the left sum (as here), the right sum, the midpoint sum, and a sum using a trapezoidal approximation of the rectangle area.

For left, right, and midpoint sums, n function values are required for n subintervals. When the trapezoidal approximation is used, n+1 function values are required.

7 0
1 year ago
What is the length of line segment FE?
Jobisdone [24]

Answer:

(7,-1)because it is problem of vector lesson so that we have to use formula of vector

6 0
3 years ago
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Which ordered pairs are solutions to the inequality 2x y&gt;−42x y&gt;−4? select each correct answer. (4, −12) (5, −12) (0, 1) (
andreyandreev [35.5K]
2x+y>-4,     2*5-12=10-12= - 2, -2 > -4 (5, -12) matched,  2*0 + 1= 1> - 4,  (0,1) matched, 2*-1 + (-1) = -3 > -4, (-1,-1) matched, the solutions are (5, -12) ,  (0,1)  and (-1,-1), if the question is 2x+y>-4, 
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3 years ago
Math again yay!...Ew math
Sliva [168]

Answer:

The graph of g(x) is wider.

Step-by-step explanation:

Parent function:

f(x)=x^2

New function:

g(x)=\left(\dfrac{1}{2}x\right)^2=\dfrac{1}{4}x^2

<u>Transformations</u>:

For a > 0

f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}

f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}

\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of}\:a\\ & \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a\\\end{aligned}

\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of} \: a\\& \textsf{If }a > 1 \textsf{ it is compressed by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of}\: a\\\end{aligned}

If the parent function is <u>shifted ¹/₄ unit up</u>:

\implies g(x)=x^2+\dfrac{1}{4}

If the parent function is <u>shifted ¹/₄ unit down</u>:

\implies g(x)=x^2-\dfrac{1}{4}

If the parent function is <u>compressed vertically</u> by a factor of ¹/₄:

\implies g(x)=\dfrac{1}{4}x^2

If the parent function is <u>stretched horizontally</u> by a factor of ¹/₂:

\implies g(x)=\left(\dfrac{1}{2}x\right)^2

Therefore, a vertical compression and a horizontal stretch mean that the graph of g(x) is wider.

4 0
2 years ago
An indoor running track is 200 meters in length. During a 3,000-meter race, runners must complete 15 laps of the track. An elect
Vlad1618 [11]

The true statement based on the histogram is

There were no lap times between 35 and 36 seconds.

The correct option is (A).

<h3>What is Histogram?</h3>

A histogram is a graphical representation that organizes a group of data points into user-specified ranges.

Given:

indoor running track is 200 meters in length.

Also, a 3,000-meter race, runners must complete 15 laps of the track.

As, there no data for interval 35-36.

So, there were no lap times between 35 and 36 seconds.

Hence, The interval from 37 to 38 seconds saw the most lap times.

Learn more about histogram here:

brainly.com/question/16819077

#SPJ1

8 0
2 years ago
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