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IRISSAK [1]
4 years ago
10

Please help me !! Simplify 5 - (-1)

Mathematics
2 answers:
sergiy2304 [10]4 years ago
6 0

Answer:

6

Step-by-step explanation:

5+1

a negative and a negative make a positive.

=6

ANEK [815]4 years ago
6 0

Answer:

6

Step-by-step explanation:

minus and minus together make a plus so the equation simplifies to 5 + 1 nad that equals 6

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Given parallelogram ABCD, m\angle A=5x+18 and m\angle B=3x-6 find find m\ C
WARRIOR [948]

Answer:

57

Step-by-step explanation:

Firstly, we will need to calculate what x is.

To calculate this, the important property of the parallelogram to use is that adjacent angles are supplementary.

This means A and B are supplementary while B and C are also supplementary

what we are trying to say is that they add up to be 180

Thus,

5x + 18 + 3x -6 = 180

8x +12 = 180

8x = 180-12

8x = 168

x = 168/8

x = 21

Thus, the measure of angle B is 3x-6 = 3(21) -6 = 63-6 = 57

Now, another important property of parallelograms is that opposite angles are equal. This means that angle B= C = 57

6 0
3 years ago
If one class collected 65 cans for the food drive and another class collected 176 cans, how many cans did the two classes collec
kotegsom [21]
In this equation C means the total. In order to find the total you must add the two class together to get the total. The equation that represents this would be the fourth one. 65 + 176 = C
7 0
4 years ago
Read 2 more answers
3. f(x) = 56x<br> Find the y-intercept and inverse of the exponential functions
ivann1987 [24]

Y intercept : ( 0,0 )

Inverse :

\frac{x}{56}

3 0
3 years ago
What is m∠G to the nearest tenth?
vitfil [10]

Answer:

Step-by-step explanation:

tan(G) = 28.2/45.8

G = arctan(28.2/45.8) = 31.6°

4 0
3 years ago
For what value of k are there two complex solutions to the given quadratic equation (k+1)x²+4kx+2=0.
nlexa [21]

Answer:k\in \left ( \frac{-1}{2},1\right )

Step-by-step explanation:

Given

\left ( k+1\right )x^2+4kx+2=0

For complex  roots Discriminant should be zero

D<0

D=\sqrt{b^2-4ac}

here

D=\sqrt{\left ( 4k\right )^2-4\left ( k+1\right )\left ( 2\right )}

D=\sqrt{16k^2-8k-8}

so 16k^2-8k-8

2k^2-k-1

\left ( 2k+1\right )\left ( k-1\right )

so k\in \left ( \frac{-1}{2},1\right )

3 0
4 years ago
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