Answer:
6 root two
Step-by-step explanation:
geometric mean for leg t.
24*3=x2
x2=72
x=root(72)
6 root two
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Answer:
She spent $26.50
Step-by-step explanation:
subtract $18.50 from $45.00
Answer: (3a + 1) (a + 3)
Step-by-step explanation:
<u>Concept:</u>
Here, we need to know the idea of factorization.
It is like "splitting" an expression into a multiplication of simpler expressions. Factoring is also the opposite of Expanding.
<u>Solve:</u>
Given = 3a² + 10a + 3
<em>STEP ONE: separate 3a² into two terms</em>
3a
a
<em>STEP TWO: separate 3 into two terms</em>
3
1
<em>STEP THREE: match the four terms in ways that when doing cross-multiplication, the result will give us 10a.</em>
3a 1
a 3
When cross multiply, 3a × 3 + 1 × a = 10a
<em>STEP FOUR: combine the expression horizontally to get the final factorized expression.</em>
3a ⇒ 1
a ⇒ 3
(3a + 1) (a + 3)
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Answer:
7.5
*
10
^-
4
Step-by-step explanation:
Answer:
- number of multiplies is n!
- n=10, 3.6 ms
- n=15, 21.8 min
- n=20, 77.09 yr
- n=25, 4.9×10^8 yr
Step-by-step explanation:
Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...
mpy[n] = n·mp[n-1]
mpy[2] = 2
So, ...
mpy[n] = n! . . . n ≥ 2
__
If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...
10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10
Then the larger matrices take ...
n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min
n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years
n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years
_____
For the shorter time periods (less than 100 years), we use 365.25 days per year.
For the longer time periods (more than 400 years), we use 365.2425 days per year.