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Delicious77 [7]
3 years ago
10

Find the inverse y=3x+2

Mathematics
1 answer:
Gwar [14]3 years ago
4 0

y=3x+2\\\\\text{replace x with y and y with x}\\\\3y+2=x\\\\\text{solve for y}\\\\3y+2=x\ \ \ \ \ |-2\\\\3y=x-2\ \ \ \ \ |:3\\\\\boxed{y=\dfrac{x-2}{3}}

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What is the coefficient in the expression -5x + 8
Katen [24]
I really need points sorryyyyyyyy
5 0
3 years ago
Solve the graph to find
Juliette [100K]

Answer:

Step-by-step explanation:

x=3            x=2.        x=1

y=1 *3        y=1 *2.       y=1 *1

y=1               y=1.       y=1

(3,1).            (2,1)        (1,1)

‘The others are the same. Probably you can use a calculator too

8 0
3 years ago
A survey of 500 high school students was taken to determine their favorite chocolate candy. Of the 500 students surveyed, 42 lik
Step2247 [10]

Answer:

Step-by-step explanation:

Universal set

U = 500

The number that likes snickers

n(S) = 42

The number that like Twix.

n(T) = 110

The number that like Reeses

n(R) = 125

n(S n T) = 33

n(T n R) = 62

n(S n R) = 26

n( S n R n T) = 22

Then,

n(S n T) only = n(S n T) - n(S n R n T)

n(S n T) only =33 - 22 = 11

n(T n R) only = n(T n R) - n(S n R n T)

n(T n R) only =62 - 22 = 40

n(S n R) only = n(S n R) - n(S n R n T)

n(S n R) only =26 - 22 = 4.

Also,

n(S) only = n(S) - n(S n R) - n(S n T) only

n(S) only = 42 - 26 - 11 = 5

n(T) only = n(T) - n(T n R) - n(T n S) only

n(T) only = 110 - 62 - 11 = 37

n(R) only = n(R) - n(S n R) - n(R n T) only

n(R) only = 124 - 26 - 40 = 58

Then, to know if some student don't like any of the of chocolate,

Let know the number of students that like the chocolate candy

n(S) + n(T)only + n(T n R)only + n(R) only

42 + 37 + 40 + 58 = 177 students.

Therefore, the total students that like chocolate candy is 177, so those  that does not like any of them are

n(S U R U T)' = U – n(S U R U T)

n(S U R U T) = 500 - 177 = 323.

So, the question is how many student likes at most 2 kinds of these chocolates, this means that they can like exactly 2 or less or even none.

So, this category are

n(2 most) = n(S n T)only + n(R n T)only + n(S n R)only + n(s)only + n(T)only + n(R)only + n(S U R U T)'

n(2 most) = 11 + 40 + 4 + 5 + 37 + 58 + 323

n(2 most) = 478

The correct answer is E.

Check attachment for Venn diagram

5 0
3 years ago
4. What is 54 + (-78) - (-39)
inysia [295]

Answer:

Step-by-step explanation:

follow the Pemdas order of operations

add and subtract (left to right)

apply the rule +(-a)=-a

+(-78)=-78

=54-78-(-39)

54-78=-24

=-24-(-39)

apply the rule -(-a)=+a

-(-39) =+39

=-24 +39

-24+39=15

=15

5 0
1 year ago
Each person attending a two-day conference receives 4 meal vouchers to use.
Lisa [10]
Part A: Let x and y be the number of persons attending the two-day conference and y be the number of vouchers released. The equation that would best express the given is,
                                             y = 4x

Part B: The number of people attending the conference is determined by dividing the given number of vouchers by 4. The answer is 956. 
6 0
3 years ago
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