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Mathematics

2 answers:

kompoz [17]2 years ago

4 0

Bearing is just taking reference from the north. In this case Q to point Pat which has three 90 Degree points and the angle of 45 Degrees
In this case you can write it as this vvv
—90+90+90+45=315 Degrees

iren [92.7K]2 years ago

3 0

Step-by-step explanation:

${3}^{2} + {3}^{2} = 2 \times {3}^{2} = 18 \\ \sqrt{18} = 4.24 \: km$

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1.What is the equation of the line perpendicular to that passes through ? Write your answer in slope-intercept form. Show your

Juliette [100K]

Answer:

1. Use a compass to make arc marks which intersect above and below then connect.

2. $y=\frac{1}{3}x + 2$

Step-by-step explanation:

1. To construct a perpendicular line, use a compass to draw arc marks from one end of the segment through point P. Then repeat this again at the other end. This means at point P there will be two intersecting arc marks. Repeat the process down below with the same radius as used above. Then connect the two intersections.

2. The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=-3\\y_1=1$ . We write

$(y-1)=m(x--3)\\(y-1)=m(x+3)$

Since the line is to be perpendicular to the line shown it will have the negative reciprocal to the slope of the function 3x+y =-8. To find m, rearrange the function to be y=-8-3x. The slope is -3 and the negative reciprocal will be 1/3.

$(y-1)=\frac{1}{3}(x+3)$