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3 years ago

Work is due in 2 hours

Mathematics

2 answers:

kompoz [17]3 years ago

4 0

Bearing is just taking reference from the north. In this case Q to point Pat which has three 90 Degree points and the angle of 45 Degrees
In this case you can write it as this vvv
—90+90+90+45=315 Degrees

iren [92.7K]3 years ago

3 0

Step-by-step explanation:

${3}^{2} + {3}^{2} = 2 \times {3}^{2} = 18 \\ \sqrt{18} = 4.24 \: km$

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Illusion [34]

Answer:

The answer is "717.25 minutes".

Step-by-step explanation:

In this question first, we arrange the value in ascending order that are:

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$Average = \frac{(425 +435)}{2} = \frac{(860)}{2} =430$

Because as medium stands at 10.5 that median is as below 10 are greater than the level.

$Q_1$ often falls throughout the ordered BELOW average is $= \frac{(n+1)}{2}$ place.

$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered position

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$Q_1 = \frac{(354+363)}{2} = \frac{(717)}{2}= 358.5$

In $= \frac{(n+1)}{2}$ the ordered place, Q3 always falls ABOVE the median.

$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered At median ABOVE

Consequently $Q_3$ falls between $5^{th} \ and \ 6^{th}$ ABOVE the median position

$15^{th}\ and \ 16^{th}$ place average of observations

$\to Q_3 = \frac{(499+505)}{2}=\frac{(1004)}{2} = 502$

$\to IQR = Q_3 - Q_1= 502-358.5= 143.5$

$\to \text{Upper fence} = Q_3 + 1.5 \times IQR= 502 + 1.5 \times 143.5 = 717.25$

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Work is due in 2 hours​

Work is due in 2 hours