Question

The function gx is defined as gx=6x^2+23x-4,when does g(x)=0

Answer 1

For this case we have the following function:

$g (x) = 6x ^ 2 + 23x-4$

What we must do is find the zeros of the function.

We have then:

 $6x ^ 2 + 23x-4 = 0$

Factoring we have:

$(x + 4) (6x-1) = 0$

From here, we solve the solutions of the equation:

Solution 1:

$x + 4 = 0 x = -4$

Solution 2:

 $6x-1 = 0$

$x = \frac{1}{6}$

Answer:

The values of x that make the equation equal to zero are:

$x = -4$

$x = \frac{1}{6}$

Answer 2

The given function is

$g(x) = 6x^2 +23x-4$

And we have to find the value of g(0), and for that we put 0 for x in the given equation.

And on substituting 0 for x in the given expression, we will get

$g(0) = 6(0)^2 +23(0) -4$

$g(0) = 0 + 0 -4 = -4$

So for the given function, the value of g(0) is -4 .