Using a discrete probability distribution, it is found that:
a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.
b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.
c) The expected value is of 1.3 lawns mowed on a randomly selected day.
<h3>What is the discrete probability distribution?</h3>
Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:
Item a:
P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.
Item b:

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.
Item c:
The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:
E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.
The expected value is of 1.3 lawns mowed on a randomly selected day.
More can be learned about discrete probability distributions at brainly.com/question/24855677
Answer:
Domain: {-5,-1,3} and Range: {3,0,-4,2}
Step-by-step explanation:
Just take my word for it please.
Answer: 
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Explanation:
r = number of red pens
4r = cost of buying r red pens
example: if r = 10, then 4r = 4*10 = 40 is the total cost of buying 10 red pens
If John buys r red pens, then he must buy 20-r black pens so that r and 20-r add to 20.
John buys 20-r black pens, and at $5 each, so it will cost 5(20-r) dollars for just the black pens alone.
In total, John spends 4r + 5(20-r) dollars for all the pens (red & black)
We want $92 be the most he spends. This is the ceiling or highest value possible.
Therefore,

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Extra info:
If you want to solve for r, then

distribute

add r to both sides

subtract 92 from both sides


So John must buy at least 8 red pens. The most he can buy is 20 red pens since he wants 20 pens total.
The period required to pay for the car is not given. However let us assume this interest rate of 6.5% is per annum, on simple interest terms.
I= PRT
where I is the interest accrued, P is the principal, R is the rate and T is the time.
If the car is paid for in one year then the final cost will be:
I = 29990 × 6.5% × 1
6.5% must be expressed as a decimal fraction so we divide by 100 to get 0.065
I= 29990 × 0.065 × 1
I = 1,949.35
29990 + 1949.35 = 31939.35 dollars.
If the car is paid for in five years on simple interest terms then the final cost will be :
I = 29990 × 0.065 ×5 = 9,746.75
29990 + 9.746.75 = 39,736.75 dollars
The answer is 3 ! 3 times three equals 9