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3 years ago

Which is an example of an algebraic expression? A. 2k + 25 B. z – 8 = 44 C. 3 + 7 = 10 D. 76 – 10

Mathematics

2 answers:

photoshop1234 [79]3 years ago

7 0

Options a and b are the algebraic expressions

Brrunno [24]3 years ago

5 0

B. would be a great example of an algebraic expression

Please mark as brainliest answer

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Why is

zloy xaker [14]

Answer:

Only natural numbers (i.e., non-negative integers) can be the exponents of variables in a polynomial.

Step-by-step explanation:

The exponent of variables in a polynomial should be natural numbers ( $0$ , $1$ , $2$ , $3$ , $\dots$ .)

$\sqrt{2\, x}$ is equal to $\sqrt{2}\, x^{1/2}$ . In this expression, $x$ is the variable. Its exponent is $1/2$ , which isn't a natural number.

On the other hand, $\sqrt{2}\, x$ is equivalent to $\sqrt{2}\, x^{1}$ . The exponent of variable $x$ is $1$ , which is indeed a natural number.

$\sqrt{2\, x}$ isn't a polynomial because the exponent of variable $x$ isn't a natural number. On the other hand, $\sqrt{2}\, x$ is indeed a polynomial over the set of real numbers.

3 0

3 years ago

Use cylindrical coordinates to evaluate the triple integral ∭ where E is the solid bounded by the circular paraboloid z = 9 - 16

4vir4ik [10]

Answer:

$\mathbf{\iiint_E E \sqrt{x^2+y^2} \ dV =\dfrac{81 \ \pi}{80}}$

Step-by-step explanation:

The Cylindrical coordinates are:

x = rcosθ, y = rsinθ and z = z

From the question, on the xy-plane;

$9 -16 (x^2 + y^2) = 0 \\ \\ 16 (x^2 + y^2) = 9 \\ \\ x^2+y^2 = \dfrac{9}{16}$

$x^2+y^2 = (\dfrac{3}{4})^2$

where:

0 ≤ r ≤ $\dfrac{3}{4}$ and 0 ≤ θ ≤ 2π

∴

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} \int ^{9-16r^2}_{0} \ r \times rdzdrd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} r^2 z|^{z= 9-16r^2}_{z=0} \ \ \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} r^2 ( 9-16r^2}) \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} ( 9r^2-16r^4}) \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( \dfrac{9r^3}{3}-\dfrac{16r^5}{5}})|^{\dfrac{3}{4}}_{0} \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( 3r^3}-\dfrac{16r^5}{5}})|^{\dfrac{3}{4}}_{0} \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}}) d \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV =( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}}) \theta |^{2 \pi}_{0}$

$\iiint_E E \sqrt{x^2+y^2} \ dV =( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}})2 \pi$

$\iiint_E E \sqrt{x^2+y^2} \ dV =(\dfrac{81}{64}}-\dfrac{243}{320}})2 \pi$

$\iiint_E E \sqrt{x^2+y^2} \ dV =(\dfrac{81}{160}})2 \pi$

$\mathbf{\iiint_E E \sqrt{x^2+y^2} \ dV =\dfrac{81 \ \pi}{80}}$

4 0

3 years ago

What is the value of "?" if the Perimeter = 50 km?

777dan777 [17]

Answer:

14km

Explanation

11km + 11km = 22km is the sum of both the width.

If you want to find the length than minus the perimeter with 22.

50km - 22km = 28km is the sum of both the length.

To know only one side of the length, divide it by 2.

28km/2 = 14km is the length

6 0

3 years ago

The diameter of a wheel of a car is 0.75 m. if the car travels at an average speed of 14 m/s, find the

raketka [301]

Step-by-step explanation:

Circumference of wheel = πd = 0.75πm.

How far the car travels per minute

= 60s * (14m/s) = 840m.

Hence number of revolutions per minute

= 840m / 0.75πm

= 356.507....

= 357. (nearest whole number)

6 0

3 years ago

Is the following a reflection,<br> rotation or translation?

Blababa [14]

Rotation

It’s rotating 90 degrees counterclockwise

5 0

3 years ago