Answer:
no solutions
Step-by-step explanation:
n+(-n) = 3+ 15
n+-n = 0
0= 18
False
There are no solutions
1. Line l; point P not on l.( Take a line I and mark point P outside it or on the line.So from point P there are infinite number of lines out of which only one line is parallel to line I. Suppose you are taking point P on line I, from that point P also infinite number of lines can be drawn but only one line will be coincident or parallel to line I.
2. Plane R is parallel to plane S; Plane T cuts planes R and S.(Imagine you are sitting inside a room ,consider two walls opposite to each other as two planes R and S and floor on which you are sitting as third plane T ,so R and S are parallel and plane T is cutting them so in this case their lines of intersect .But this is not possible in each and every case, suppose R and S planes are parallel to each other and Plane T cuts them like two faces of a building and third plane T is stairs or suppose it is in slanting position i.e not parallel to R and S so in this case also lines of intersection will be parallel.
3. △ABC with midpoints M and N.( As you know if we take a triangle ABC ,the mid points of sides AB and AC being M and N, so the line joining the mid point of two sides of a triangle is parallel to third side and is half of it.
4.Point B is between points A and C.( Take a line segment AC. Mark any point B anywhere on the line segment AC. Three possibilities arises
(i) AB > BC (ii) AB < BC (iii) AB = BC
Since A, B,C are collinear .So in each case 
11 is b because the bottom needs to be 5 to dived the amount by 5 minutes and the top is the amount of words she types in 5 minutes
Micah is 5 inches shorter than twice the height of Jasmine
Micah = 5 inches shorter than 2 x Jasmine
Micah = 2 x Jasmine - 5 <em>(jasmine is 32 inches tall. Replace jasmine with 32)
</em>
Micah = 2 x 32 - 5
Micah = 64 - 5
Micah = 59
Micah is 59 inches tall
Answer:

Step-by-step explanation:
ΔPQS, ΔRQP and ΔRPS are similar (AA). Therefore the sides are in proportion:

We have:

Substitute:
<em>cross multiply</em>

Use the Pythagorean theorem:

Substitute:
