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Darya [45]
2 years ago
15

The dot plots below show the scores for a group of students for two rounds of a quiz: Which of the following inferences can be m

ade using the dot plots? The range of round 2 is greater than the round 1 range. Round 2 scores are higher than round 1 scores. Round 1 scores are lower than round 2 scores. There is no overlap between the data.

Mathematics
1 answer:
victus00 [196]2 years ago
7 0
<h3>Answer: Choice A) round 2 has larger range</h3>

===================================================

Explanation:

  • Choice A is true. The range is the difference of the max and min. Round 1 has a range of 5-4 = 1, while round 2's range is 5-1 = 4. Round 2 has a larger range of scores. We don't really need to do any kind of math here. We can simply spot that round 2 has its dots more spread out compared to round 1, so round 2 must have the larger range.
  • Choice B is somewhat true. If we compare a score of 4 in round 1 to a score of 5 in round 2, then round 2 has a higher score. But we could easily flip things around. So saying one round has higher scores than the other is not particularly meaningful in this scenario. I would say it all depends on how you phrase the problem carefully. In any event, I would say that choice B is false since we can't definitively say it's true.
  • Choice C is a similar story as choice B, just flip things around. So I'd say this is false too. We would need all of the dots of round 1 to be to the left of all the dots of round 2, in order for choice C to be a true statement. Because there's overlap, we run into a problem.
  • Choice D is false because there is overlap for scores 4 and 5. In other words, both dot plots have dots over "4" and over "5". These are the scores the dot plots share in common.
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Find the 12th term of the geometric sequence 5, -25, 125, ...5,−25,125,...
katovenus [111]

Answer:

  • a_{12}=-244140625

Step-by-step explanation:

Considering the geometric sequence

5,-25,\:125,\:...

a_1=5

As the common ratio 'r' between consecutive terms is constant.

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

r=\frac{-25}{5}=-5

r=\frac{125}{-25}=-5

The general term of a geometric sequence is given by the formula:  

a_n=a_1\cdot \:r^{n-1}

where a_1 is the initial term and r the common ratio.

Putting n = 12 , r = -5 and a_1=5 in the general term of a geometric sequence to determine the 12th term of the sequence.

a_n=a_1\cdot \:r^{n-1}

a_n=5\left(-5\right)^{n-1}

a_{12}=5\left(-5\right)^{12-1}

      =5\left(-5^{11}\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

       =-5\cdot \:5^{11}

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

        =-5^{1+11}     ∵ 5\cdot \:5^{11}=\:5^{1+11}

        =-244140625

Therefore,

  • a_{12}=-244140625
6 0
3 years ago
If 3220 = 80+7, what is the value of c?
Setler79 [48]

Answer:

Correct option is

C

36.25

Modal class =30−40

So we have, l=30,f0=12,f1=32,f2=20 and h=10

⇒  Mode=l+2f1−f0f2f1−f0×h

                  =30+2×32−12−2032−12×10

                  =30+6.25

                  =36.25

∴  Mode =36.25

8 0
2 years ago
The coordinate of centroid of a triangle whose vertices are (1,3,-2), (4,5,0), (6,3,9) is = ……………….
Dominik [7]

Answer:

C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})

Step-by-step explanation:

Given

(x_1,y_1,z_1) = (1,3,-2)

(x_2,y_2,z_2) = (4,5,0)

(x_3,y_3,z_3) = (6,3,9)

Required

Determine the coordinates of the centroid

Represent the coordinates with C.

C is calculated as follows:

C = (\frac{1}{3}(x_1+x_2+x_3),\frac{1}{3}(y_1+y_2+y_3),\frac{1}{3}(z_1+z_2+z_3}))

Substitute values of x and y in the given equation

C = (\frac{1}{3}(1+4+6),\frac{1}{3}(3+5+3),\frac{1}{3}(-2+0+9}))

C = (\frac{1}{3}(11),\frac{1}{3}(11),\frac{1}{3}(7}))

C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})

<em>The above is the coordinate of the centroid</em>

8 0
2 years ago
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vichka [17]

Answer:

4/9 ÷ 17/18 =

Step-by-step explanation:

4/9 ÷ 17/18

4/9 · 18/17      (Take the reciprocals of 17/18)

72/153

Simplest form : 8/17

Hope this helps!

-Abha

8 0
3 years ago
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Pani-rosa [81]

Answer:

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if additive inverse then

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if multiplicative inverse then

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if both then

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if in this way

f(x)=(1/3x)-7

f(-x)=(-1/3)-7

7 0
3 years ago
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