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gavmur [86]
2 years ago
11

Which shows the four-term polynomial and factored form of x2 6x – 27? x2 3x – 9x – 27 = (x 3)(x – 9) x2 6x – 3x– 27 = (x 6)(x –

3) x2 9x – 3x – 27 = (x 9)(x – 3) x2 3x – 6x – 27 = (x 3)(x – 6).
Mathematics
1 answer:
Rainbow [258]2 years ago
8 0

None of the polynomials has four terms in it.

<h2>Polynomial </h2>

It is the sum of terms in which the variable is in decreasing power of n.

<h2>Given</h2>

Polynomial is in factor form

\rm 1.\  (x^{2} )(6x-27)(x^{2} )(3x)(-9x -27)\\&#10;2.\  (x^{3} )(x-9)(x^{2} )(6x)(-3x-27)\\&#10;3.\  (x^{6} )(x-3)(x^{2} )(9x)(-3x-27)\\&#10;4.\  (x^{9} )(x-3)(x^{2} )(3x)(-6x-27)\\&#10;5.\  (x^{3} )(x-6)

<h2>How to solve polynomial? </h2>

\begin{aligned} \rm 1.\  &(x^{2} )(6x-27)(x^{2} )(3x)(-9x -27)\\&#10;&-162x^{7}- 243x^{6} +2187x^{5} \\&#10;2.\  &(x^{3} )(x-9)(x^{2} )(6x)(-3x-27)\\&#10;&-18x^{8} +1458x^{6} \\&#10;3.\  &(x^{6} )(x-3)(x^{2} )(9x)(-3x-27)\\&#10;&-27x^{11}-162 x^{10} 729x^{9} \\&#10;4.\  &(x^{9} )(x-3)(x^{2} )(3x)(-6x-27)\\&#10;-&18x^{13} -27x^{12} +243x^{11} \\&#10;5.\  &(x^{3} )(x-6)\\&#10;&x^{4} -6x^{3} \\&#10;\end{aligned}

Thus, none of the polynomials has four terms in it.

More about the polynomial link is given below.

brainly.com/question/17822016

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