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3 years ago

What is the diameter, circumference, and area of a circle that has the radius of 7?

Mathematics

2 answers:

Natasha2012 [34]3 years ago

7 0

Answer:

14, 616, 154

Step-by-step explanation:

area of circle πr^2

diameter= r x 2

circumference=πd^2

user100 [1]3 years ago

4 0

Answer:

the diameter is: 14

the circumference is: C≈43.98

the area is: A≈153.94

Step-by-step explanation:

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374x+3=2995 ME GIVE BRAIN I MUST DO MY HOMEWORK you lifesaver...

Kaylis [27]

Hi there!

x=8

1.Subtract the answer with the 3 / subtract the terms:

$2995-3=2992$

2.Divide the two terms:

$2992*374=x$

Therefore, x=8

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2 years ago

How much was shoes and shirt before went on sale

babymother [125]

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2 years ago

Here are 2 bowls. One of them has 25 gems and the other has 15 gems. Some of them are red.All the gems from the two bowls are no

spin [16.1K]

Answer:

the answer is $\frac{25}{15}\\$ Hope this helps :}

Step-by-step explanation:

Here are 2 bowls. One of them has 25 gems and the other has 15 gems. Some of them are red. All the gems from the two bowls are now put into a third bowl. What fraction of the gems in the third bowl will be red?

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3 years ago

What are the solutions of 4x2 + x = -3? (5 points) and x2 - 7x = -12 (5 points)

Yuki888 [10]

4x^2 + x + 3 = 0

x = [-1 +/- sqrt (1^2 - 4 * 4 * 3)] / 8 = - 1 +/- sqrt ( --47) / 8

= ( - 1 +/- sqrt47i) / 8 = -0.125 + 0.857i , -0.125 - 0.857i

7 0

3 years ago

Read 2 more answers

Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or

WARRIOR [948]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8$

compare them away.

4 0

3 years ago