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FromTheMoon [43]

3 years ago

13

When p = 12, t = 2, and s = 1/6 , r = 18. If r varies directly with p and inversely with the product of s and t, what is the con

stant of variation?

2 answers:

ICE Princess25 [194]3 years ago

8 0

Answer:

1/2 should be your answer

Step-by-step explanation:

Nataliya [291]3 years ago

5 0

Set it up:

18 = 12 / (2 x .167)

18 = 36k

k = 1/2

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-7(a - 3) = 11 - 7a<br> what’s the answer

natali 33 [55]

Answer:

the statement is false there is no solution

Step-by-step explanation:

step 1 -7(a-3)=11-7a

step 2 -7a+21=11-7a

step 3 cancel out the -7a's

step 4 you are left with 21=11 which does not work so it is false

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2 years ago

A $50.00 pair of shoes is discounted 20%. If sales tax is 8%, what is the amount of tax paid?

sleet_krkn [62]

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2 years ago

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11Alexandr11 [23.1K]

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2 years ago

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Help! I need the answers quick please

Norma-Jean [14]

Answer:

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Step-by-step explanation:

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2 years ago

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago