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True [87]
3 years ago
14

Justify each step in solving the equation 5(y+3)-11=-y-6 by writing a reason for each statement.

Mathematics
1 answer:
liubo4ka [24]3 years ago
6 0

Explanation:

5(y+3)-11=-y-6 Given

5(y+3)=-y+5 . . . . addition property of equality (11 is added)

5y+15=y+5 . . . . . distributive property (5 is distributed)

5y=-y-10 . . . . . . . addition property of equality (-15 is added)

6y=-10 . . . . . . . . . addition property of equality (y is added)

y=-5/3 Division Property of Equality/Reduce

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Khan academy!! Pls help will give brainllyest!!!
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Answer:

<u>C and D</u>

Step-by-step explanation:

<u>D.</u> A negative times a positive gives you a negative, so the first 2 fractions will still be negatives after they get out of the parenthesis

<u>C.</u> The 4/7 and -4/7 cancel out

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(x + 2)(x2 + 5x + + 1)
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{x}^{3}   + 7 {x}^{2}  + 11x + 2

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3 years ago
If each exterior angle of a regular polygon is 30°, find how many sides the polygon has &amp; the measure of an
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12 sides and measure of each interior angle is 150...

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3 years ago
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Given the function f)(x) =-x^2+3x+8,determine the average rate of change of the function over the interval listed in the picture
Nadusha1986 [10]

Answer:

Vertex:

(

3

2

,

−

41

4

)

(

3

2

,

-

41

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)

Focus:

(

3

2

,

−

10

)

(

3

2

,

-

10

)

Axis of Symmetry:

x

=

3

2

x

=

3

2

Directrix:

y

=

−

21

2

y

=

-

21

2

x

y

0

−

8

1

−

10

3

2

−

41

4

3

−

8

4

−

4

Vertex:

(

3

2

,

−

41

4

)

(

3

2

,

-

41

4

)

Focus:

(

3

2

,

−

10

)

(

3

2

,

-

10

)

Axis of Symmetry:

x

=

3

2

x

=

3

2

Directrix:

y

=

−

21

2

y

=

-

21

2

x

y

0

−

8

1

−

10

3

2

−

41

4

3

−

8

4

−

4

Step-by-step explanation:

7 0
3 years ago
PLS PLS HELP, I DONT WANT TO FAIL!!
Flura [38]

Answer:

2.0 seconds

Step-by-step explanation:

<u>Given quadratic functions</u>:

\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}

To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:

\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}

<u>Factor</u> the quadratic:

\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}

Apply the <u>zero-product property</u> to solve for x:

\implies (x-1)=0 \implies x=1

\implies (x-2)=0 \implies x=2

Therefore, the balloons collided at 1 second and 2 seconds.  

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

f(1)=-6(1)^2 +23(1)+5=22

f(2)=-6(2)^2 +23(2)+5=27

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

brainly.com/question/27930827

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