It is given that, B ≅ BC and AD ≅ CD
We need BD perpendicular to AC, then only we can say triangles AXB and CXB are congruent using the HL theorem.
If BD perpendicular to AC, means that AB and CB are the hypotenuse of triangles AXB and CXB respectively.
from the given information ABCD is a square
If BD and AC bisect each other then AX = CX
Then only we can immediately possible to prove that triangles AXD and CXD are congruent by SSS congruence theorem
86% written as a fraction is 43/50
Answer:
<em>The equation of the straight line in point - slope form</em>
<em>y +1 = -2 ( x-2)</em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given points are C( 2,-1) and D(1,1)
Slope of the line

m = -2
<u>Step(ii):-</u>
Equation of the straight line passing through the point ( 2,-1) and having slope
m =-2
y - y₁ = m ( x- x₁)
y - (-1) = -2 ( x-2)
y +1 = -2 ( x-2)
<u><em>Final answer:-</em></u>
<em>The equation of the straight line</em>
<em>y +1 = -2 ( x-2)</em>
Answer:
A
Step-by-step explanation:
let y = f(x) and rearrange making x the subject, that is
y =
( multiply both sides by x³ )
x³y = 19 ( divide both sides by y )
x³ =
( take the cube root of both sides )
x = ![\sqrt[3]{\frac{19}{y} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B19%7D%7By%7D%20%7D)
Change y back into terms of x, then
(x) =
=
→ A
Answer:
All work but I’d pick the 3rd one
Step-by-step explanation: