RM298
reason: multiply RM4 by 10 to get RM40 and add that to RM258 to get RM298
Problem 13
10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get
10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q
so we get the original expression again. Here 10 is the GCF of the two terms.
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Plug p = 1 and q = 2 into the factored form
10*(p+q) = 10*(1+2) = 10*(3) = 30
As a check, let's plug those p,q values into the original expression
10*p+10*q = 10*1+10*2 = 10+20 = 30
We get the same output of 30
Answer:
1/3
Step-by-step explanation:
Probability of solving ten problems by Carl
Given
Total number of problems = 20
Number of problems studied by Carl = 15
Number of problems out of the 20 set of problem coming in test is 10
Case I - All ten problems come from the set of known 15 question
10/15 * 10/20 = 1/3
Answer:
y=19/3
Step-by-step explanation:
$36 because 20% of 45 is 9 and 45 - 9 is 36!
