3 years ago

Plz help me I shan't to get done

Mathematics

1 answer:

Lelu [443]3 years ago

4 0

Answer:

Step-by-step explanation:

$-3+a$

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Line JK passes through points J(-4,-5) and K(-6,3). If the equation of the line is written in slope-intercept form, y-mx+b, what

Ksju [112]

$y=mx+b \\ \\
(x,y)=(-4,-5) \hbox{ and } (x,y)=(-6,3) \\ \Downarrow \\
-5=-4m+b \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \times (-3) \\
3=-6m+b \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\times 2 \\ \\
15=12m-3b \\
\underline{6=-12m+2b} \\
21=-b \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\times (-1) \\
\boxed{b=-21}$

The value of b is -21.

4 0

4 years ago

Read 2 more answers

Please help on this question.

Sonbull [250]

Answer:

Step-by-step explanation:

$\frac{ - 20 {x}^{2} + 14x + 12}{5x - 6} \\ \\ = \frac{- (20 {x}^{2} - 14x - 12)}{5x - 6} \\ \\ = \frac{ - (5x - 6)(4x + 2)}{5x - 6} \\ \\ = - (4x + 2 ) \\ = - 4x - 2$