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IgorC [24]
1 year ago
13

Find the probability that a single randomly selected value is greater than 204.3. Round your answer to four decimal places.

Mathematics
1 answer:
Ede4ka [16]1 year ago
8 0

The answer is P(>204.3) = 0.5000

There are an infinite number of real numbers > 204.3, but an equally infinite number of real numbers < 204.3

The chance of randomly selecting a number >204.3 is 1/2 or 50%

or for 4 decimals: 50.0000%

The probability of an event can be calculated via chance formula with the aid of truly dividing the favorable range of effects by means of the whole number of feasible effects.

Opportunity = the wide variety of ways of achieving fulfillment. The whole range of viable effects. As instance, the possibility of flipping a coin and it being head is ½, because there is 1 way of having a head and the whole range of viable effects is two (a head or tail).

Chance is the department of mathematics that research the possible outcomes of given occasions together with the outcomes' relative likelihoods and distributions.

Learn more about the probability here brainly.com/question/24756209

#SPJ4

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Three businesswomen are trying to convene in Northwest Arkansas for a business meeting. The first (Woman 1) is arriving on a fli
boyakko [2]

Answer:

a) The probability mass function of X is then presented in the table below.

X | probability P(X=x) or p

0 | 0.001

1 | 0.032

2 | 0.283

3 | 0.684

b) The cumulative distribution function of X

Cdf = Σ pdf = P(X=0) + P(X=1) + P(X=2) + P(X=3)

= 1.000

c) The probability that at least two businesswomen arrive on time

P(X ≥ 2) = P(X=2) + P(X=3) = 0.967

d) Expected value of X = E(X) = 2.65

e) Standard deviation = 0.545

Step-by-step explanation:

The probability that the woman coming from Atlanta arrives on time = P(A) = 0.90

The probability that the woman coming from Atlanta DOES NOT arrive on time = P(A') = 1 - 0.90 = 0.10

The probability that the woman coming from Dallas arrives on time = P(B) = 0.95

The probability that the woman coming from Dallas DOES NOT arrive on time = P(B') = 1 - 0.95 = 0.05

The probability that the woman coming from Chicago arrives on time = P(C) = 0.80

The probability that the woman coming from Chicago DOES NOT arrive on time = P(C') = 1 - 0.80 = 0.20

Since X is the random variable that represents how many women arrive on time,

To evaluate the probability function, we will first obtain the probability that the number of women that arrive in time = 0, 1, 2, and 3.

First probability; that no woman arrives on time. X = 0

P(X=0) = P(A') × P(B') × P(C')

= 0.10 × 0.05 × 0.20

P(X=0) = 0.001

Second probability; that only one of the women arrive on time. X = 1

P(X=1) = [P(A) × P(B') × P(C')] + [P(A') × P(B) × P(C')] + [P(A') × P(B') × P(C)]

= [0.90 × 0.05 × 0.20] + [0.10 × 0.95 × 0.20] + [0.10 × 0.05 × 0.80]

= 0.009 + 0.019 + 0.004

P(X=1) = 0.032

Third probability; that only two women arrive on time. X = 2

P(X=2) = [P(A) × P(B) × P(C')] + [P(A) × P(B') × P(C)] + [P(A') × P(B) × P(C)]

= [0.90 × 0.95 × 0.20] + [0.90 × 0.05 × 0.80] + [0.10 × 0.95 × 0.80]

= 0.171 + 0.036 + 0.076

P(X=2) = 0.283

Fourth probability; that all 3 women arrive on time. X = 3

P(X=3) = P(A) × P(B) × P(C)

= 0.90 × 0.95 × 0.8

P(X=3) = 0.684

The probability mass function of X is then presented in the table below.

X | probability P(X=x) or p

0 | 0.001

1 | 0.032

2 | 0.283

3 | 0.684

b) The cumulative distribution function of X

Cdf = Σ pdf = P(X=0) + P(X=1) + P(X=2) + P(X=3)

= 0.001 + 0.032 + 0.283 + 0.684 = 1.000

c) The probability that at least two businesswomen arrive on time

P(X ≥ 2) = P(X=2) + P(X=3) = 0.283 + 0.684 = 0.967

d) Expected value of X

Expected value is given as

E(X) = Σ xᵢpᵢ

E(X) = (0)(0.001) + (1)(0.032) + (2)(0.283) + (3)(0.684) = 0 + 0.032 + 0.566 + 2.052 = 2.65

e) What is the standard deviation of X?

Standard deviation = √(variance)

Variance = Var(X) = Σx²p − μ²

μ = E(X) = 2.65

Σx²p = (0²)(0.001) + (1²)(0.032) + (2²)(0.283) + (3²)(0.684)

= (0)(0.001) + (1)(0.032) + (4)(0.283) + (9)(0.684)

= 0 + 0.032 + 1.132 + 6.156

= 7.32

Variance = Var(X) = 7.32 - 2.65² = 7.32 - 7.0225

Var(X) = 0.2975

Standard deviation = √(variance) = √0.2975

Standard deviation = 0.545

Hope this Helps!!!

8 0
3 years ago
12, 17, 22, ...<br> Find the 36th term.
pychu [463]

Answer:

187

Step-by-step explanation:

a=12,d=17-12=5

nth term =a+(n-1)d

36th term=12+(36-1)5

=12+(35×5)

12+175

36th term=187

8 0
2 years ago
Bruce has a bottle with 60% lemon juice and the rest water.
Dimas [21]
The percent of water would be 40%
3 0
3 years ago
Solve for the width in the formula for the area of a triangle
zmey [24]

Answer: \frac{2A}{h} = w

Step-by-step explanation:

The formula for area of a triangle is A = wh\frac{1}{2}

Now we have to isolate for w.

First multiply by the 2 which is the reciprocal of 1/2 to cancel it out.

2A = wh\\

Now divide by h to isolate w.

\frac{2A}{h} = w

4 0
2 years ago
You have 6L of water that has 20 percent strawberry juice. How many litres of an 80 percent strawberry juice should be added to
Kaylis [27]

Answer:

you are right

Step-by-step explanation:

7 0
2 years ago
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